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pantera1 [17]
3 years ago
5

Distinguish between exponentiation and modulus. Be specific.

Computers and Technology
1 answer:
fredd [130]3 years ago
7 0

Answer:

Exponentiation: Exponentiation is a mathematical operation involving raising a base to an exponent.

Modulo: The modulo operation finds the remainder after division of one number by another.

Explanation:

You might be interested in
A teacher wants to create a list of students in her class. Using the existing Student class in this exercise. Create a static Ar
aleksandr82 [10.1K]

Answer:

Check the explanation

Explanation:

CODE:-

import java.util.ArrayList;

class Student

{

  private String name;

  private int grade;

  private static ArrayList<Student> classList = new ArrayList<Student>();

 

  public Student(String name, int grade)

  {

      this.name = name;

      this.grade = grade;

      classList.add(this);

  }

 

  public String getName()

  {

      return this.name;

  }

 

  /*Don't change the code in this method!

  This method will print out all the Student names in the classList Array

  */

  public static String printClassList()

  {

      String names = "";

      for(Student name: classList)

      {

          names+= name.getName() + "\n";

      }

      return "Student Class List:\n" + names;

  }

}

public class ClassListTester

{

  public static void main(String[] args)

  {

      //You don't need to change anything here, but feel free to add more Students!

      Student alan = new Student("Alan", 11);

      Student kevin = new Student("Kevin", 10);

      Student annie = new Student("Annie", 12);

      Student smith = new Student("Smith", 11);

      Student kane = new Student("Kane", 10);

      Student virat = new Student("Virat", 12);

      Student abd = new Student("ABD", 12);

      Student root = new Student("Root", 12);

      System.out.println(Student.printClassList());

  }

}

Kindly check the attached image below.

4 0
3 years ago
In a two-sided tag, a(n) ____ tag indicates the content's end.
alexira [117]

Answer:

A closing tag

Explanation:

A tag in HTML is the core building block that marks the presence of an element. If the element has text or another element within it, it is marked using a two-sided tag and in which case, the opening tag indicates the content’s beginning and a closing tag indicates the end of the content

7 0
3 years ago
Read 2 more answers
A Lost link is an interruption or loss of the control link between the control station and the unmanned aircraft, preventing con
Vlad [161]

Answer:

There is nothing to answer from this statement.

Explanation:

Can you rephrase the statement into question?

4 0
3 years ago
Mike has never used a slide software before, but he needs to create a presentation by the end of the week. what recourse would b
ankoles [38]

This is an incomplete question. The complete question is given below:

Mike has never used slide presentation software before but he needs to create a presentation by the end of the week what resource would be most helpful to mike

a. The 350-page printed manual from the slide presentation software publisher

b. A free tutorial the slide presentation software publisher has posted on the company website

c. A trouble-shooting website created by a third party

d. The 350-page online manual from the slide presentation software publisher

Answer:

b - A free tutorial the slide presentation software publisher has posted on the company website

Explanation:

As Mike has a short time and no prior experience with a slide software, then in this scenario, the best, simplest and fastest way to learn and create a presentation a free tutorial which the slide presentation software publisher has posted on the company website  as this is the same company that has created this particular software so he can be rest-assured that the resource he is relying on is authentic and up-to-date with information on latest features.

Moreover, it's efficient and quick way to learn from a free tutorial rather than from 350-page printed or online manual especially for a beginner.

Besides, his purpose is to create the presentation using the software and not trouble-shooting so trouble-shooting website created by a third party is not useful for him and it also might not be authentic or updated as well.

6 0
3 years ago
Write a Java class to perform the following: 1. Write a method to search the following array using a linear search, ( target ele
Alina [70]

Answer:

Check the explanation

Explanation:

Linear search in JAVA:-

import java.util.Scanner;

class linearsearch

{

  public static void main(String args[])

  {

     int count, number, item, arr[];

     

     Scanner console = new Scanner(System.in);

     System.out.println("Enter numbers:");

     number = console.nextInt();

   

     arr = new int[number];

     System.out.println("Enter " + number + " ");

     

     for (count = 0; count < number; count++)

       arr[count] = console.nextInt();

     System.out.println("Enter search value:");

     item = console.nextInt();

     for (count = 0; count < number; count++)

     {

        if (arr[count] == item)

        {

          System.out.println(item+" present at "+(count+1));

         

          break;

        }

     }

     if (count == number)

       System.out.println(item + " doesn't found in array.");

  }

}

Kindly check the first attached image below for the code output.

Selection Sort in JAVA:-

public class selectionsort {

   public static void selectionsort(int[] array){

       for (int i = 0; i < array.length - 1; i++)

       {

           int ind = i;

           for (int j = i + 1; j < array.length; j++){

               if (array[j] < array[ind]){

                   ind = j;

               }

           }

           int smaller_number = array[ind];  

           array[ind] = array[i];

           array[i] = smaller_number;

       }

   }

     

   public static void main(String a[]){

       int[] arr = {9,94,4,2,43,18,32,12};

       System.out.println("Before Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

       System.out.println();

         

       selectionsort(arr);

       

       System.out.println("After Selection Sort");

       for(int i:arr){

           System.out.print(i+" ");

       }

   }

}  

Kindly check the second attached image below for the code output.

Bubble Sort in JAVA:-

public class bubblesort {

   static void bubblesort(int[] array) {

       int num = array.length;

       int temp = 0;

        for(int i=0; i < num; i++){

                for(int j=1; j < (num-i); j++){

                         if(array[j-1] > array[j]){

                           

                                temp = array[j-1];

                                array[j-1] = array[j];

                                array[j] = temp;

                        }

                         

                }

        }

   }

   public static void main(String[] args) {

               int arr1[] ={3333,60,25,32,55,620,85};

               

               System.out.println("Before Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

               System.out.println();

                 

               bubblesort(arr1);

               

               System.out.println("After Bubble Sort");

               for(int i=0; i < arr1.length; i++){

                       System.out.print(arr1[i] + " ");

               }

 

       }

}  

Kindly check the third attached image below for the code output.

Binary search in JAVA:-

public class binarysearch {

  public int binarySearch(int[] array, int x) {

     return binarySearch(array, x, 0, array.length - 1);

  }

  private int binarySearch(int[ ] arr, int x,

        int lw, int hg) {

     if (lw > hg) return -1;

     int middle = (lw + hg)/2;

     if (arr[middle] == x) return middle;

     else if (arr[middle] < x)

        return binarySearch(arr, x, middle+1, hg);

     else

        return binarySearch(arr, x, lw, middle-1);

  }

  public static void main(String[] args) {

     binarysearch obj = new binarysearch();

     int[] ar =

       { 22, 18,12,14,36,59,74,98,41,23,

        34,50,45,49,31,53,74,56,57,80,

        61,68,37,12,58,79,904,56,99};

     for (int i = 0; i < ar.length; i++)

        System.out.print(obj.binarySearch(ar,

           ar[i]) + " ");

     System.out.println();

     System.out.print(obj.binarySearch(ar,19) +" ");

     System.out.print(obj.binarySearch(ar,25)+" ");

     System.out.print(obj.binarySearch(ar,82)+" ");

     System.out.print(obj.binarySearch(ar,19)+" ");

     System.out.println();

  }

}

Kindly check the fourth attached image below for the code output

7 0
3 years ago
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