Answer:
![4](https://tex.z-dn.net/?f=4)
Step-by-step explanation:
The line passes through points ![(2,0)\,,\,(0,2)](https://tex.z-dn.net/?f=%282%2C0%29%5C%2C%2C%5C%2C%280%2C2%29)
Let ![(x_1,y_1)=(2,0)\,,\,(x_2,y_2)=(0,2)](https://tex.z-dn.net/?f=%28x_1%2Cy_1%29%3D%282%2C0%29%5C%2C%2C%5C%2C%28x_2%2Cy_2%29%3D%280%2C2%29)
Equation of a line passing through points
is given by ![y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)](https://tex.z-dn.net/?f=y-y_1%3D%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D%28x-x_1%29)
![y-0=\frac{2-0}{0-2}(x-2)\\y=\frac{2}{-2}(x-2)\\y=-1(x-2)\\y=-x+2](https://tex.z-dn.net/?f=y-0%3D%5Cfrac%7B2-0%7D%7B0-2%7D%28x-2%29%5C%5Cy%3D%5Cfrac%7B2%7D%7B-2%7D%28x-2%29%5C%5Cy%3D-1%28x-2%29%5C%5Cy%3D-x%2B2)
So,
![f(x)=y=-x+2](https://tex.z-dn.net/?f=f%28x%29%3Dy%3D-x%2B2)
Put ![x=-2](https://tex.z-dn.net/?f=x%3D-2)
![f(-2)=-(-2)+2=2+2=4](https://tex.z-dn.net/?f=f%28-2%29%3D-%28-2%29%2B2%3D2%2B2%3D4)
Answer:
(- 10, 5 )
Step-by-step explanation:
Given the 2 equations
5x + 12y - 10 = 0 ( add 10 to both sides )
5x + 12y = 10 → (1)
2x - 3y + 35 = 0 ( subtract 35 from both sides )
2x - 3y = - 35 → (2)
Multiplying (2) by 4 and adding to (1) will eliminate the y- term
8x - 12 y = - 140 (3)
Add (1) and (3) term by term
5x + 8x + 12y - 12y = 10 - 140, that is
13x = - 130 ( divide both sides by 13 )
x = - 10
Substitute x = - 10 into either (1) or (2) and solve for y
Substituting in (1)
5(- 10) + 12y = 10
- 50 + 12y = 10 ( add 50 to both sides )
12y = 60 ( divide both sides by 12 )
y = 5
Solution is (- 10, 5 )
First you subtract -9 on both sides and -9-9=0 so then you just have 4n so you divide on both sides and you get n=0
The student made error in step 2 because negative multiplied by positive is negative. Also negative multiplied by negative is positive