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Vlad [161]
3 years ago
8

Nolini says that if the denominator is more than twice the numerator, the fraction can always be replaced with a 0. Is she corre

ct? Give an example in your explanation.
Mathematics
1 answer:
Len [333]3 years ago
5 0

Answer:

yes

Step-by-step explanation:

It depends on how accurate you want your answer to be, but basically yes, imagine we set our numerator to be x, and our denominator to be 2x, if we built our fraction we will get that:

\frac{x}{2x}=\frac{1}{2}

If the denominator of a fraction is exactly twice the numerator, then the fraction will be simplified to 1/2 or 0.5.

Now, the greater the denominator is, the closer the fraction will get to zero.

Take for example I had an fraction like this:

\frac{3}{6}=0.5

which approximates to 0. If we made the denominator bigger, let's say 7, we would get:

\frac{3}{7}=0.43

notice the answer is closer to 0 this time, so it's valid to round it to zero. If we made the denominator greater, let's say 25, we would get:

\frac{3}{25}=0.12

and so on. So it is true that if the denominator of a fraction is greater than twice the numerator, we can always replace the fraction with a 0 (depending on how accurate you want your answer to be).

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Someone pls help I need assistance
lutik1710 [3]

Answer:

A: tan(25)

Step-by-step explanation:

Hopefully this helps

3 0
3 years ago
Need help in graphing this function.
bearhunter [10]
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2 years ago
Everyone at Jaylen's school wore either brown or blue for school spirit day. 90 students wore brown and 10 students wore blue. W
NISA [10]

Answer:

90%

Step-by-step explanation:

90 + 10 is 100 total

90/100 is just 90%

6 0
3 years ago
Read 2 more answers
Each year, all final year students take a mathematics exam. It is hypothesized that the population mean score for this test is 8
drek231 [11]

Answer:

95% Confidence interval:  (96.06,103.94)

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 85

Sample mean, \bar{x} = 100

Sample size, n = 30

Alpha, α = 0.05

Population standard deviation, σ = 11

95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

100 \pm 1.96(\frac{11}{\sqrt{30}} ) = 100 \pm 3.94= (96.06,103.94)

(96.06,103.94) is the 95% confidence interval for  the population mean test score.

8 0
3 years ago
Solve 2x - 11 = k for x.
denis23 [38]
2x + -11 = k

Reorder the terms:
-11 + 2x = k

Solving
-11 + 2x = k

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 2x = 11 + k

Combine like terms: -11 + 11 = 0
0 + 2x = 11 + k
2x = 11 + k

Divide each side by '2'.
x = 5.5 + 0.5k

Simplifying
3 0
3 years ago
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