Answer:
the company must buy 22 gallons to paint this entire area
Step-by-step explanation:
The circumference of the tank is given and is C = 2(pi)r, where r is the area.
118 ft
Here the circumference is C = 2(pi)(r) = 118 ft, which leads to r = ------------ ≈
18.79 ft ≈ r 2(pi)
The area of the sides is A = (circumference)(height), or approximately
(118 ft)(50 ft) = 5900 ft², and the area of the top is A = πr², which here comes to (π)(18.79 ft)² ≈ 1109 ft². Combining these two sub-areas, we get:
A(total) = 1109 ft² + 5900 ft² ≈ 7009 ft²
To determine how many gallons of paint will be needed to paint only the top and sides, we divide 7009 ft² by the coverage rate, which is
320 ft²
-----------
1 gallon
which results in:
7009 ft²
---------------------- ≈ 21.9 gallons
320 ft² / gallon
Since the paint comes only in full gallon cans, the company must buy 22 gallons to paint this entire area.
From inspecting the graph, you can identify the y-intercept and the slope of the line shown.
The y-intercept is 200 gallons.
The slope is
75-200
m = ------------- = -12.5 gallons/minute
10 - 0
Thus, y = 200 gallons - [12.5 gallons/minute ]t
To answer the 2nd question, let t = 12 minutes and calculate y(12).
To determine how long it wld take to empty the tank, set the above formula equal to zero and solve the resulting equation for t.
The answer is D
real explanation: take 0.642 & divide it by -0.28.
