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2 years ago

HELP WITH ALL PLZ I NEED HELP

Mathematics

1 answer:

alex41 [277]2 years ago

4 0

1.) 16/100 and 0.16
2.) 7/10 and 0.7
3.) 6/10
4.) 73/100
5.) 6 9/10
6.)8 57/100
7.)0.70
8.)0.33
9.)7.20
10.)3.09
11.) 0.80
12.)0.48
13.)0.02
14.)0.55
15.)D
I hope all of these are correct and help

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A rectangle is constructed with its base on the x-axis and two of its vertices on the parabola yequals=4949minus−xsquared2. Wha

xxMikexx [17]

Answer:

Dimensions of rectangle : Width = $2x$ , Length = $49 - x^2$

Area of Rectangle = $98x - 2x^3$

Step-by-step explanation:

A rectangle constructed with its base on the x-axis and two of its vertices on the parabola

Supposing coordinates of upper right vertex of rectangle are P = $(x,y)$

Due to parabola symmetry, width of rectangle is twice the horizontal (X) axis distance between Y axis & point P.

Width of rectangle : $2x$

Length of rectangle : $y = 49 - x^2$

Area of Rectangle = Length x Width

( $2x$ ) ( $49 - x^2$ )

= $98x - 2x^3$

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2 years ago

Rafael needs to drive 16 miles to work.so far, he has driven 4.1 miles.How many more miles must he drive

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2 years ago

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Rent and other associated housing costs, such as utilities, are an important part of the estimated costs of attendance at colleg

zhenek [66]

Answer:

96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

Step-by-step explanation:

We are given that a group of researchers at the BYU Off-Campus Housing department want to estimate the mean monthly rent that unmarried BYU students paid during winter 2018.

During March 2018, they randomly sampled 314 BYU students and found that on average, students paid $346 for rent with a standard deviation of $86.

So, the pivotal quantity for 95% confidence interval for the average age is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = average rent paid by 314 BYU students = $346

s = sample standard deviation = $86

n = sample of students = 314

$\mu$ = population mean monthly rent of all unmarried BYU students

So, 96% confidence interval for the population mean monthly rent, $\mu$ is ;

P(-2.082 < $t_3_1_3$ < 2.082) = 0.96

P(-2.082 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.082) = 0.96

P( $-2.082 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.082 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

P( $\bar X -2.082 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X +2.082 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

96% confidence interval for $\mu$ = [ $\bar X -2.082 \times {\frac{s}{\sqrt{n} } }$ , $\bar X +2.082 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $346 -2.082 \times {\frac{86}{\sqrt{314} } }$ , $346 +2.082 \times {\frac{86}{\sqrt{314} } }$ ]

= [335.89 , 356.10]

Therefore, 96% confidence interval estimate for the mean monthly rent of all unmarried BYU students in winter 2018 is [335.89 , 356.10].

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