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andriy [413]
3 years ago
9

How many quarts of pure antifreeze must be added to 2 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution?

Mathematics
1 answer:
vovikov84 [41]3 years ago
4 0

Answer:

Let x = amount (quarts) of pure antifreeze added

then

x + .10(2) = .40(x+2)

x + .20 = .40x+.80

x = .40x+.60

.60x = .60

x = 1.0 quart

Step-by-step explanation:

Hope this helps!

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Write and solve a real-world problem that can be modeled by the equation 0.75 - 18.50 = 0.65x
jenyasd209 [6]

Answer:

Step-by-step explanation:

Sam bought a chocolate. He ate some and leaving 0.75 for Alice.

Alice ate 18.50 grams of chocolate and return the rest to Sam, which was 65% of the original chocolate.  How much chocolate did Sam had at the beginning?

Now solve the equation:

0.75x - 18.50 = 0.65x

Combine the like terms:

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x=185

This shows that Sam had 185 grams of chocolate...

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There are already derived equations for this so it is already convenient. However, your given equation for range is incomplete. The correct equation is:

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