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77julia77 [94]
3 years ago
8

Evaluate a + b2 for a = 2 and b = 3. 8 11 25

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
4 0
<span>a + b^2 for a = 2 and b = 3
= 2 + 3^2
= 2 + 9
= 11
answer
11</span>
mamaluj [8]3 years ago
3 0
8

a+b2
replace the letter with it's number
2+3(2)
multiply 3 and 2
2+6
add
8
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The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit fo
FinnZ [79.3K]
Hello, I have done this same math question before.

1. 15 dollars
2. Deposit=15*month+105
3. Deposit=15*12+105=$285
4. 500=15*month+105
    395=15*month
    26.33=month
    Round up to 27 for the nearest whole month, so month 27.

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4 0
3 years ago
According to the U.S. Bureau of Labor Statistics, 20% of all people 16 years of age or older do volunteer work. In this age grou
Murljashka [212]

Answer:

1. P(X≥35) = 0.0183

2. P(X≤21) = 0.0183

3. P(0.18<p<0.25) = 0.7915

Step-by-step explanation:

We have the proportion for women: pw=0.22, and the proportion for men: pm=0.19.

1. We have a sample of 140 woman and we have to calculate the probability of getting 35 or more who do volunteer work.

This is equivalent to a proportion of

p=X/n=35/140=0.25

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.22*0.78}{300}}\\\\\\ \sigma_p=\sqrt{0.0006}=0.0239

We calculate the z-score as:

z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.25-0.22}{0.0239}=\dfrac{0.03}{0.0239}=0.8198

Then, the probability of having 35 women or more who do volunteer work in this sample of 140 women is:

P(X>35)=P(p>0.25)=P(z>2.0906)=0.0183

2. We have to calculate the probability of having 21 or fewer women in the group who do volunteer work.

The proportion is now:

p=X/n=21/140=0.15

We can calculate then the z-score as:

z=\dfrac{p-p_w}{\sigma_p}=\dfrac{0.15-0.2}{0.0239}=\dfrac{-0.05}{0.0239}=-2.0906

Then, the probability of having 21 women or less who do volunteer work in this sample of 140 women is:

P(X

3. For the sample with men and women, we use the proportion for both, which is π=0.2.

The sample size is n=300.

Then, the standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.2*0.8}{300}}\\\\\\ \sigma_p=\sqrt{0.0005}=0.0231

We can calculate the z-scores for p1=0.18 and p2=0.25:

z_1=\dfrac{p_1-\pi}{\sigma_p}=\dfrac{0.18-0.2}{0.0231}=\dfrac{-0.02}{0.0231}=-0.8660\\\\\\z_2=\dfrac{p_2-\pi}{\sigma_p}=\dfrac{0.25-0.2}{0.0231}=\dfrac{0.05}{0.0231}=2.1651

We can now calculate the probabilty of having a proportion within 0.18 and 0.25 as:

P=P(0.18

5 0
4 years ago
A has the coordinates (-4,3) and B has the coordinates (4,4). If Do1/2 (x,y) is a dialation of ABC, what is true about the image
coldgirl [10]
The answer is e c and a I took the test
4 0
3 years ago
Please answer I need help
Goryan [66]

Answer:

Maybe 3 1/2 but they don't give enough information

8 0
3 years ago
Will mark you as brain pls help meeee
stich3 [128]

Answer:

c. overload

Step-by-step explanation:

4 0
3 years ago
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