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kiruha [24]
3 years ago
7

Please answer I need help

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

Maybe 3 1/2 but they don't give enough information

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What is the equation of a line that has a slope of-2/3 and a y intercept of 1.25
Fynjy0 [20]

Answer:

The equation of this line would be y = -2/3x + 1.25

Step-by-step explanation:

In order to find this, first start with the base form for slope-intercept form.

y = mx + b

Now input the slope for m and the intercept for b.

y = -2/3x + 1.25

4 0
3 years ago
Chris’s bank allows him to have a negative balance in his checking account. Chris initially has $450 in his account. He then wri
Cloud [144]

x=Money after withdrawals.

x=450-200(3)

x=450-600

x=-250

After making 3 $200 withdrawals from his account after initially starting with $450 he has a balance of negative $250 in his account.

4 0
3 years ago
What is the surface area of this cone?
DanielleElmas [232]

surface area of this cone?

Use A= 3.14 and round your answer to the nearest hundredth

9 ft

6 ft

8 0
3 years ago
Find the average rate of change of g(x) = 1x3 + 2 from x =<br> 1 to x = 4
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Explanation:

The

average rate of change

of g(x) over an interval between 2 points (a ,g(a)) and (b ,g(b) is the slope of the

secant line

connecting the 2 points.

To calculate the average rate of change between the 2 points use.

∣

∣

∣

∣

∣

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

a

a

g

(

b

)

−

g

(

a

)

b

−

a

a

a

∣

∣

∣

−−−−−−−−−−−−−−−

g

(

6

)

=

6

2

−

6

+

3

=

33

and

g

(

4

)

=

4

2

−

4

+

3

=

15

Thus the average rate of change between (4 ,15) and (6 ,33) is

33

−

15

6

−

4

=

18

2

=

9

This means that the average of all the slopes of lines tangent to the graph of g(x) between (4 ,15) and (6 ,33) is 9

3 0
3 years ago
The graph of f(x) = x3 − 7x − 6 is shown. Based on the graph, what are all of the solutions to f(x) = x3 − 7x − 6? x = −6 x = −2
pogonyaev
F(x)=x^3-7x-6  Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P

x-(f(x)/(dy/dx))

x-(x^3-7x-6)/(3x^2-7)

(2x^3+6)/(3x^2-7), letting x1=0

0, -6/7, -.988, -.9999, -.99999999999, -1

(x^3-7x-6)/(x+1)

x^2 r -x^2-7x-6
-x   r  -6x-6
-6   r  0

(x+1)(x^2-x-6)=0

(x+1)(x-3)(x+2)=0

x= -2, -1, 3 


4 0
3 years ago
Read 2 more answers
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