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anygoal [31]
3 years ago
6

1.What is the term referring to an amount of money that is owed?

Computers and Technology
2 answers:
horsena [70]3 years ago
8 0

Answer:

Debt?

Explanation:

BARSIC [14]3 years ago
6 0

Answer:

debt

Explanation:

ur welcome brody

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Which best describes the benefits of renting a home? ARenting can cost more upfront. BRenting is less flexible than owning a hom
yulyashka [42]

Renting can be an alternative to many people, especially those in areas where house prices are very expensive. The benefits to renting a home, however, are not mentioned in the given question, making the best answer (D) none of the above.

Some actual benefits that a person can gain are actually flexibility, since renting means that you can easily move from one place to another compared to buying a home, where you require capital and selling the previous home also falls into your responsibility, while rentals are managed by landlords.

8 0
3 years ago
What commands does SuperKarel know that regular Karel does not?
luda_lava [24]

Answer:

turnRight and turnaround

Explanation:

The regular karel does not know these commands

5 0
2 years ago
Write a program to output the following quote by Edsger W. Dijkstra:
adell [148]

Answer:

#include<iostream>

using namespace std;

main(){

cout<<"\*Computer Science is no more about computers \n than astronomy is about telescopes"<<endl;

}

Explanation:

using c++

5 0
2 years ago
Read 2 more answers
What obstacles could prevent you from getting and keeping a job
stepladder [879]
Drugs, No Collage, Gangs, bad grades, Criminal Records →
7 0
3 years ago
Two files named numbers1.txt and numbers2.txt both have an unknown number of lines, each line consisting of a single positive in
Reika [66]

Answer:

see explaination for program code

Explanation:

scalar_product = 0

li=[]

li2=[]

#reading numbers1.txt and numbers2.txt intoli and li2 respectively

with open('numbers1.txt') as n1, open('numbers2.txt') as n2:

for line1 in n1:

li.append(int(line1))

for line2 in n2:

li2.append(int(line2))

#storing min list size into variable l

a=len(li)

b=len(li2)

if a<b:

l=a

else:

l=b

#calculating scalar product

for i in range(l):

scalar_product=scalar_product+li[i]*li2[i]

print("scalar product is",scalar_product)

6 0
3 years ago
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