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zubka84 [21]
4 years ago
9

. Two or more functions may have the same name, as long as their _________ are different.

Computers and Technology
1 answer:
nikdorinn [45]4 years ago
8 0

Answer:

Number of parameters.

Explanation:

The function is a block of the statement which performs the special task.

Syntax:

type name(parameter_1,parameter_2,...){

statement

}

we can define any number of function in the code and also with the name as well.

But when we define the function with same name the number of parameter define in both function must be different.

for example:

1. int print(int a){

statement;

}

2. int print(int a, int b){

statement;

}

first has one parameter and second has two parameters.

Both are valid in the code.

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3 years ago
Write a for loop that will print the values 1 to 20 while skipping the odd numbers (2,4,6,8,10,12,14,16,18,20):
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<u>Answer:</u>

<em>void main ( )  </em>

<em> {  </em>

<em> int counter;  </em>

<em>  cout<<""Even numbers between 1 to 20 are:""<<endl ;  </em>

<em> //Method 1 </em>

<em>  for (counter = 1; counter <= 20; counter++)  </em>

<em>  {  </em>

<em>    if ( counter%2 == 0)  </em>

<em>   {   </em>

<em>     cout<<counter<<""\t""<<endl ;  </em>

<em>   }  </em>

<em>  }  </em>

<em>//Method 2 – simplest one </em>

<em>for (counter = 2; counter <= 20;)  </em>

<em>  {  </em>

<em>     cout<<counter<<""\t""<<endl ;  </em>

<em>counter = counter + 2; </em>

<em>    </em>

<em>  } </em>

<em> </em>

<em>  return 0;  </em>

<em>} </em>

<u>Explanation:</u>

In this, Method 1 runs a for loop and check whether each number is divided by 2. If yes, then printed otherwise it is skipped.

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