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Artemon [7]
4 years ago
11

There are 18 girls in a basketball team. If the starting lineup consists of 5 players, then how many possible starting lineups a

re there?
A. 90 lineups
B. 1,889,568 lineups
C. 1,028,160 lineups
D. 8,568 lineups



Please help!!! I’m so confused
:(
Mathematics
2 answers:
vichka [17]4 years ago
8 0
The answer would be 90 line ups

This is because 18 x 5 = 90
hichkok12 [17]4 years ago
7 0

Answer:

I belive the answer A) 90 lineups

Step-by-step explanation:

All you would have to do is multiply 18 by 5 and you would get 90.

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Find the probability of getting a king then an eight. Assume the cards are not replaced?
Nastasia [14]
There are 4 king and 4 eight cards inside 52 one deck of cards. The case asks for a king card and then an eight card. 
To draw the king card, you have 4/52 probability.
To draw the eight card, you have 4/51 probability ( since the king card not replaced).

The total probability would be: 4*4/ 52*51= 4/663

4 0
3 years ago
8 - 4y + (-2y) + 5 <br><br><br> What is this answer please tell me
Irina-Kira [14]

Answer:

<em>13 - 6y </em>

Step-by-step explanation:

8 - 4y + (-2y) + 5 = <em>13 - 6y</em>

8 0
3 years ago
Read 2 more answers
Given the function f(x) = 2(3)x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3.
jeyben [28]

f(0) = 2(3)(0) = 0  ⇒  (0, 0)

f(1) = 2(3)(1) = 6  ⇒  (1, 6)

<u>rate of change from x = 0 to x = 1</u>

\frac{y2 - y1}{x2 - x1} = \frac{6 - 0}{1 - 0} = \frac{6}{1} = 6

******************************************

f(2) = 2(3)(2) = 12  ⇒  (2, 12)

f(3) = 2(3)(3) = 18  ⇒  (3, 18)

<u>rate of change from x = 2 to x = 3</u>

\frac{y2 - y1}{x2 - x1} = \frac{18 - 12}{3 - 2} = \frac{6}{1} = 6

*****************************************

Since it is the same line, they will have the same slope (aka rate of change).

5 0
3 years ago
Can someone plz help me with this
Anna007 [38]
I’m not sure that this is 100% right but i would do tan37° x 12 to get: -10.1
7 0
3 years ago
A wildlife audit was recently conducted in Port Augusta, the results of which were as follows: Amphibians Insects Fish Reptiles
r-ruslan [8.4K]

Answer:

The relative frequency of mammals in the survey is 30%.

Step-by-step explanation:

Relative frequency is the ratio of the occurrence of a singular event and the total number of outcome

Amphibians  Insects  Fish  Reptiles  Birds  Mammals

12                 30          9          25        22        42

Relative frequency = = \frac{\text{ (number of trials that are successful)}}{\text{(total number of trials)}}

Total number of wildlife animals  = 12+ 30 +9 +25+22+42 = 140

Now the relative frequency of mammals in the survey = \frac{\text{total number of mammals}}{\text{ Total number of animals}}

the relative frequency of mammals in the survey =\frac{42}{140} = 0.3

Converting into percentage , we get

=0.3 \times 100

= 30 %

5 0
3 years ago
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