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Over [174]
3 years ago
14

A number increased by the sum of the number and four is 20. Find the number.

Mathematics
1 answer:
miss Akunina [59]3 years ago
7 0

Answer:

i think 5 is the right answer

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Which of the following values are solutions to the inequality x-7< 5?x−7<5?
Lunna [17]

Answer:

x>12

Step-by-step explanation:

7 0
3 years ago
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What is the absolute value of 6
Pie

The answer is 6 that's how many places its away from zero.

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Solve using the quadratic formula. Show all work. Write each solution in simplest form. No decimals.
alexira [117]

Answer:

Option B

Step-by-step explanation:

Given quadratic equation is,

12a² + 9a + 7 = 0

By comparing this equation with standard quadratic equation,

hx² + kx + c = 0

h = 12, k = 9 and c = 7

By using quadratic formula,

a = \frac{-k\pm\sqrt{k^2-4hc}}{2h}

  = \frac{-9\pm\sqrt{9^2-4(12)(7)}}{2(12)}

  = \frac{-9\pm\sqrt{81-336}}{2(12)}

  = \frac{-9\pm\sqrt{-255}}{24}

  = \frac{-9\pm i\sqrt{255}}{24}

a = \frac{-9+ i\sqrt{255}}{24},\frac{-9- i\sqrt{255}}{24}

Therefore, Option B will be the correct option.

3 0
3 years ago
Help due today asap Plaese help
fomenos

Answer:

A

Step-by-step explanation:

8 0
3 years ago
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What line is parallel to 2x+5y=6 that goes through (5,3)
Anna11 [10]

Answer:

4y = x - 17

Step-by-step explanation:

First off, in the equation given : 2x + 5y = 6 , make y the subject of the formula which will give y = \frac{-2x}{5} + \frac{6}{5}  which make the gradient, m, the coefficient of x = \frac{-2}{5}  . Since the line we're looking for is parallel to the one we were given, their respective gradients would be the same. (If they were perpendicular, the gradient of the new line would be a negative inverse of the given line)

Then you proceed to use the one-point formula : y - y₀ = m(x - x₀), where   y₀ = 3 and x₀ = 5 from the point it goes through (5, 3)

y - 3 = \frac{1}{4}(x - 5); y - 3 = \frac{x}{4} - \frac{5}{4};  y = \frac{x}{4} - \frac{5}{4} +3

y = \frac{x}{4} - \frac{17}{4};  y = \frac{x-17}{4}  ;   4y = x - 17

7 0
2 years ago
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