Solve for xxx. 12x+7 4012x+7 4012, x, plus, 7, is less than, minus, 11, start color #ed5fa6, start text, space, O, R, space, end
gregori [183]
Answer:
<h2>
x < -3/2 and x>48/5</h2>
Step-by-step explanation:
Given the inequality function 12x+7< -11 and 5x-8>40, we are to solve for the value of x. To solve for x, the following steps must be followed.
For the inequality 12x+7< -11
Step 1: Subtract 7 from both sides of the inequality
12x+7-7< -11-7
12x < -18
Step 2: Divide both sides of the inequality by 12
12x/12 < -18/12
x < -3/2 .............. 1
For the inequality 5x-8> 40;
Step 1: Add 8 to both sides of the inequality
5x-8+8 > 40+8
5x > 48
Step 2: Divide both sides of the inequality by 5
5x/5 > 48/5
x>48/5....... 2
Combining equation 1 and 2, we will have;
x < -3/2 and x>48/5
If x>48/5 then 48/5<x
Combining 48/5<x with x < -3/2 will give 48/5<x<-3/2
Its D. they are equidistant from the center of the circle , just took the test and that was the answer on apex
12 4/15 is the answer simplified
Answer:
3rd option: x= 40
Step-by-step explanation:
4x° +20°= 180° (adj. ∠s on a str. line)
<em>Bringing</em><em> </em><em>constants</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>:</em>
4x°= 180° -20°
<em>Simplify</em><em>:</em>
4x°= 160°
<em>Divide</em><em> </em><em>by</em><em> </em><em>4</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
x°= 40°
Thus, x=40.
<u>Given</u>:
Given that the isosceles trapezoid JKLM.
The measure of ∠K is 118°
We need to determine the measure of each angle.
<u>Measure of ∠L:</u>
By the property of isosceles trapezoid, we have;
Thus, the measure of ∠L is 62°
<u>Measure of ∠M:</u>
By the property of isosceles trapezoid, we have;
Substituting the value, we get;
Thus, the measure of ∠M is 62°
<u>Measure of ∠J:</u>
By the property of isosceles trapezoid, we have;
Substituting the value, we get;
Thus, the measure of ∠J is 118°
Hence, the measures of each angles of the isosceles trapezoid are ∠K = 118°, ∠L = 62°, ∠M = 62° and ∠J = 118°
