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3 years ago

What is the volume of the cylinder below?

Mathematics

2 answers:

dolphi86 [110]3 years ago

7 0

For this case we have that, by definition, the volume of a cylinder is given by the following formula:

$V = \pi * r ^ 2 * h$

Where do we have to:

A: It's the radio

h: It's the height

We have to:

$h = 3\\r = 8$

Substituting the values we have:

$V = \pi * (8) ^ 2 * 3\\V = \pi * 64 * 3\\V = 192 \pi \ units ^ 3$

Answer:

Option C

Ede4ka [16]3 years ago

5 0

Answer: hey, the answer will be choice number 2 or b

Step-by-step explanation:

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I need help With this I will mark you if your awnser is right

ElenaW [278]

Answer:

$\boxed {\sf Equation: 60 \textdegree +4x= 180 \textdegree} \\$

$\boxed {\sf x=30}$

Step-by-step explanation:

The interior angles of a triangle must add to 180 degrees.

In this triangle, the angles are A, B , and C. So,

∠A + ∠B + ∠C= 180°

∠A is 60 degrees, ∠B is 3x, and ∠C is x. We can substitute the values in.

60°+3x+x=180°

This is the equation we can use to find the value of x.

We also have like terms: 3x and x that can be combined.

60° + (3x+x)= 180°
60° + 4x=180°

We can use the equation to solve for x. We have to isolate the variable.

60 is being added to 4x. The inverse of addition is subtraction. Subtract 60 from both sides of the equation.

60°-60°+4x=180°-60°
4x= 180°-60°
4x=120°

x is being multiplied by 4. The inverse of multiplication is division. Divide both sides by 4.

4x/4= 120°/4
x= 120°/4
x=30

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3 years ago

Need help finding out the recursive Formula? Please Help! Really stuck on this problem. Thank you!!

natima [27]

I have included the answer in the picture attached below:

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3 years ago

Find the area of a regular nonagon with a side length of 9 and an apothem of 16

Sever21 [200]

Idk if i'm exactly right but i think it's 500.73

6 0

3 years ago

HURRY ANSWER AS FAST AS YOU CAN WHO EVER FINISHES FIRST I WILL MARK BRAINIEST DONT LEAVE AN EXPLANATION JUST ANSWER

iragen [17]

Answer:

A<=B

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Complex root of x^2+3x+9=0

Luden [163]

$\text{Quadratic formula}$

$ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}$

-----------------------------------------------------------------------

$x^2+3x+9=0\\\\a=1;\ b=3;\ c=9\\\\\Delta=3^2-4(1)(9)=9-36=-27\\\\\sqrt\Delta=\sqrt{-27}=\sqrt{(27)(-1)}=\sqrt{27}\cdot\sqrt{-1}=\sqrt{9\cdot3}i=\sqrt9\cdot\sqrt3i=3\sqrt3i$

$x_1=\dfrac{-3-3\sqrt3i}{2(1)}=-\dfrac{3}{2}-\dfrac{3\sqrt3}{2}i\\\\x_2=\dfrac{-3+3\sqrt3i}{2(1)}=-\dfrac{3}{2}+\dfrac{3\sqrt3}{2}i$

$i=\sqrt{-1}$

6 0

3 years ago