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Vaselesa [24]
2 years ago
15

Write the equation of a line perpendicular to the line y=-*- 3 and through (6,2).

Mathematics
1 answer:
laiz [17]2 years ago
4 0

Answer:

x=6

Step-by-step explanation:

We are given that a line y=-3 .

We have to find the line which is perpendicular to given line and passing through the point (6,2).

Given line y=-3

It is a horizontal line .

The line which is perpendicular to horizontal line is a vertical line .

The equation of vertical line is x=a

We are given that perpendicular line passing through the point (6,2).

It means the vertical line is x=6.

Therefore, the equation of perpendicular line which is passing through the point (6,2) and perpendicular to given line is given by

x=6

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Scott invests $1000 at a bank that offers 6% compounded annually.Write an equation to model the growth of the investment
gladu [14]

Answer:

Step-by-step explanation:

Using the formula for the growth of investment:

           .....[1]

where,

A is the amount after t year

P is the Principal

r is the growth rate in decimal

As per the statement:

Scott invests $1000 at a bank that offers 6% compounded annually.

⇒P = $1000 and r = 6% = 0.06

substitute these in [1] we get;

⇒

Therefore, an equation to model the growth of the investment is,

7 0
1 year ago
Find the equaton of the line passing through the points (2,11) and (-8, -19) y= ?x ?​
antoniya [11.8K]

Find the slope:

(-19 - 11) / (-8 - 2) = (-30/-10) = 3

Find the y intercept:

y = mx + b

11 = 3(2) + b

b= 5

So equation is:

y = 3x + 5

5 0
2 years ago
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
2 years ago
A student fit the line shown below to the data in the scatter plot. Which statement about the student's line is true?
Furkat [3]

Answer:

C. It is not a good fit because there are no points on the line.

Step-by-step explanation:

In order for a line to be a good fit for a data set represented as a scatterplot, the line must follow the general trend of the data in the scatterplot. This line does not follow the general trend of the data on the scatterplot, thus option (C) is the best statement to describe the situation.

C. It is not a good fit because there are no points on the line.

8 0
2 years ago
-6d - (c - d)^2 ; if c = 7 and d = 4
irina1246 [14]

Answer:

-6d - (c - d)^2 = -33

Step-by-step explanation:

-6(4) - (3)^2 =

-24 - 9 =

-33

7 0
3 years ago
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