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madreJ [45]
2 years ago
11

You randomly draw a marble from a bag, record its color, and then replace it. You draw a red marble 3 out of 20 times. What is t

he experimental probability that the next marble will be red? Write your answer as a fraction, decimal, or percent. The experimental probability that the next marble will be red is​
Mathematics
1 answer:
Mumz [18]2 years ago
6 0

Answer:

3/20 or 0.15 or 15%

Step-by-step explanation:

Since 3 red marbles were drawn out of 20 outcomes, the probability the next marble will be red is 3/20. If you convert it to a decimal it will be 0.15, and if you convert it to a percent it will be 15%.

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What is the probability of tossing a coin three times and getting tails each time?
telo118 [61]

Answer:

1/8

Step-by-step explanation:

This is a compund probability problem. You need to find the probability of each event and then multiply the probabilities together.

The probability of flipping tails is 1/2. We need three of these.

1/2 x 1/2 x 1/2 = 1/8

3 0
2 years ago
What is the midway of XY?
Lostsunrise [7]

The midpoint of XY is -0.5

7 0
3 years ago
PLEASE HELP ME!!<br> Find the length of CU.
Viktor [21]

Answer:

Did you ever find the answer? I have the same question!

Step-by-step explanation:


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3 years ago
What is the type of association between variables x and y?
Molodets [167]

Answer:

strong negative correlation

Step-by-step explanation:

if x goes up y goes down and if y goes up x comes down

8 0
3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
2 years ago
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