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Firlakuza [10]
2 years ago
9

What is the solution to this question? Plz help thx.

Mathematics
1 answer:
Doss [256]2 years ago
6 0

Answer:

Attached is the solution. Hope it helps!

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\bf \textit{logarithm of factors}\\\\
log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)
\\\\\\
\textit{Logarithm of rationals}\\\\
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
\\\\\\
\textit{Logarithm of exponentials}\\\\
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-------------------------------

\bf log(m^3n)\implies log(m^3)+log(n)\implies 3log(m)+log(n)
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\boxed{3k+v}
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log\left(\cfrac{m}{n^3}  \right)\implies log(m)-log(n^3)\implies log(m)-3log(n)
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