The answer is 7.14%
Your ruler measuring centimeters has lines for each centimeter. The rule for error is anything between 6.5 and 7.5 is considered 7cm. So the degree of error is plus or minus .5cm.
Your aim is 7cm so you divide your error of .5 by your target measurement. .5/7= 7.14 percent.
Answer:
If we define the random variable X ="time spend by the students doign homework"
And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:
Null hypothesis: ![\mu \leq 1](https://tex.z-dn.net/?f=%20%5Cmu%20%5Cleq%201)
Alternative hypothesis: ![\mu >1](https://tex.z-dn.net/?f=%5Cmu%20%3E1%20)
And they wnat to use a sample size of n = 100 and a significance level of 0.05
Step-by-step explanation:
Previous concepts
A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".
The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".
The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".
Solution to the problem
If we define the random variable X ="time spend by the students doign homework"
And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:
Null hypothesis: ![\mu \leq 1](https://tex.z-dn.net/?f=%20%5Cmu%20%5Cleq%201)
Alternative hypothesis: ![\mu >1](https://tex.z-dn.net/?f=%5Cmu%20%3E1%20)
And they wnat to use a sample size of n = 100 and a significance level of 0.05
Let's think about this. MQ is given to be a length of 24 units, PR a length of 10 whilst we must determine what length PM must be in order to satisfy the criteria of parallelogram MPQR to be a rhombus.
Assume this figure is a rhombus, rhombus MPQR. If that is so, all sides must be congruent, and the diagonals must be perpendicular ( ⊥ ) by " Properties of a Rhombus. " That would make triangle( s ) MRQ and say RMP isosceles, and by the Coincidence Theorem, MS ≅ QS, and RS ≅ PS. Therefore -
![MS = 1 / 2( 24 ) = 12 = QS,\\RS = 1 / 2( 10 ) = 5 = PS](https://tex.z-dn.net/?f=MS%20%3D%201%20%2F%202%28%2024%20%29%20%3D%2012%20%3D%20QS%2C%5C%5CRS%20%3D%201%20%2F%202%28%2010%20%29%20%3D%205%20%3D%20PS)
PS and MS are legs of a right triangle, so by Pythagorean Theorem we can determine the hypotenuse, or in other words the length of PM. This length would make parallelogram MPQR a rhombus,
![( PM )^2 = ( MS )^2 + ( PS )^2,\\PM^2 = ( 12 )^2 + ( 5 )^2,\\PM^2 = 144 + 25 = 169\\-----\\PM = 13](https://tex.z-dn.net/?f=%28%20PM%20%29%5E2%20%3D%20%28%20MS%20%29%5E2%20%2B%20%28%20PS%20%29%5E2%2C%5C%5CPM%5E2%20%3D%20%28%2012%20%29%5E2%20%2B%20%28%205%20%29%5E2%2C%5C%5CPM%5E2%20%3D%20144%20%2B%2025%20%3D%20169%5C%5C-----%5C%5CPM%20%3D%2013)
<u><em>And thus, PM should be 13 in length to make parallelogram MPQR a rhombus.</em></u>
The number that fits it is 37
I hope this helps!
Answer:
16.5
Percentage Calculator: 33 is what percent of 200? = 16.5.