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Citrus2011 [14]
3 years ago
9

What method(s) would you choose to solve the equation: x2 + 2x - 6 = 0

Mathematics
2 answers:
Nataly_w [17]3 years ago
7 0
Complete the square since can't factor
2/2=1
add 1 to both sides
x²+2x+1-6=1
factor perfect square
(x+1)²-6=1
add 6 to both sides
(x+1)²=7
sqrt both sides
x+1=+/-√7
minus 1 both sides
x=-1+/-√7


so x=-1+√7 or x=-1-√7
inn [45]3 years ago
3 0

Answer:

Quadratic formula, completing the square or graphing; the coefficient of x2 term is 1, but the equation cannot be factored.

Step-by-step explanation:

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ryzh [129]

Answer:

y=3x-1 = x=1/3

Step-by-step explanation:

y=3x-1

to find the 0-intercept at x, underline y = 0

0=3x-1

move the variable to the left side and change its sign

-3x=-1

divide both sides of the equation by -3

x=1/3

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2 years ago
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Find the perimeter of a triangle with vertices A(–3, 5), B(–3, 2), and C(1, 2)<br> Show all work
Luden [163]

Answer:

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Step-by-step explanation:

steps are in picture

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3 years ago
A jet ski rental charges a flat rate of $75, plus an additional $60 per hour. You do not want to spend more than $200. How many
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22.5

Step-by-step explanation:

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Reduce then calculate 7/8 x 4/15 x 3/7 = ? <br><br> Can you help?
Zepler [3.9K]

since this is a multiplication, all the numerators are just factors of the product numerator and all denominators are just factors of the product denominator, so we can simply reorder them some, without changing the product.


\bf \cfrac{7}{8}\times \cfrac{4}{15}\times \cfrac{3}{7}\implies \cfrac{7}{7}\times \cfrac{4}{8}\times \cfrac{3}{15}\implies \cfrac{1}{1}\times \cfrac{1}{2}\times \cfrac{1}{5}\implies \cfrac{1\cdot 1\cdot 1}{1\cdot 2\cdot 5}\implies \cfrac{1}{10}

8 0
3 years ago
What is the solution of the system equations y =-3x +8 y = -5x -2
Talja [164]

Answer:

Since both equations are equal to y, we can set them equal to each other.

y =-3x +8

y = -5x -2

-3x +8 = -5x -2

Solve for x.To do this, we need to get x by itself. First, move all the numbers to one side of the equation, and all the variables to the other.

-3x +8 = -5x -2

Add 5x to both sides

-3x+5x +8=-5x+5x -2

2x+8=-2

Subtract 8 from both sides

2x+8-8 = -2-8

2x=-10

Now, all the numbers are on one side, with the variables on the other. x is not by itself, it is being multiplied by 2. To undo this, divide both sides by 2

2x/2= -10/2

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Now, to find y, substitute -5 in for x in one of the equations.

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Put the solution into (x,y)

<u><em>The solution is (-5, 23)</em></u>

8 0
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