Want it exact? Here it is:499.243083(got it from my calculator), if rounded, then here it is:500
Answer:
1,-3,-5
Step-by-step explanation:
Given:
f(x)=x^3+7x^2+7x-15
Finding all the possible rational zeros of f(x)
p= ±1,±3,±5,±15 (factors of coefficient of last term)
q=±1(factors of coefficient of leading term)
p/q=±1,±3,±5,±15
Now finding the rational zeros using rational root theorem
f(p/q)
f(1)=1+7+7-15
=0
f(-1)= -1 +7-7-15
= -16
f(3)=27+7(9)+21-15
=96
f(-3)= (-3)^3+7(-3)^2+7(-3)-15
= 0
f(5)=5^3+7(5)^2+7(5)-15
=320
f(-5)=(-5)^3+7(-5)^2+7(-5)-15
=0
f(15)=(15)^3+7(15)^2+7(15)-15
=5040
f(-15)=(-15)^3+7(-15)^2+7(-15)-15
=-1920
Hence the rational roots are 1,-3,-5 !
Answer:
The quadratic equation is X^2 -26X +144=0
Step-by-step explanation:
You can do it shortly by using the formula
X^2-(sum)x+ product
which will give you
X^2- (8+18)x+8×18
=X^2 -26x +144
=X^2 -8x-18x + 144
=(X^2-8x)(-18x+144)
=X(X-8)-18(x-8)=0
(X-18)(X-8)=0
X-18=0 And X-8=0
X=18 X=8
. Therefore the quadratic equation is X^2 -26X +144
This is not the answer but i love ur pfp
