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3 years ago

Please answer, I don't know because I'm not the smartest.

Mathematics

1 answer:

Eva8 [605]3 years ago

7 0

Answer:

9 * l = 54

Step-by-step explanation:

You don't need to worry because you are not the smartest, everyone are different, some concepts might be difficult, but will become easy soon....

Here is the answer to your question,

area of a rectangle = length * width

( * = multiplication symbol, specifying as many feel confused )

A = l * w

Here..... A = 54 m², w = 9m

54 = l * 9 or...

9 * l = 54

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Pls help I’m failing

GuDViN [60]

Answer:

-7

Step-by-step explanation:

you divide both sides by -2 and 14/-2 is equal to -7

6 0

3 years ago

Find y when x = 15 if y = 16 when x = 30

SashulF [63]

X=15=30/2
Y=8=16/2

Y=8

6 0

3 years ago

4+3(2r+2s)+3r<br><br> Simplify this expression

Ipatiy [6.2K]

Hello!

First you can distribute the 3

4 + 6r + 6s + 3r

Then you combine like terms

4 + 9r + 6s

The answer is 9r + 6s + 4

Hope this helps!

3 0

3 years ago

The initial size of the population is 300. After 1 day the population has grown to 800. Estimate the population after 6 days. (R

Cloud [144]

Solution :

Given initial population = 300

Final population after 1 day = 800

Number of days = 6

∴ $\frac{dP}{dt} =kt^{1/2}$

P(0) = 300 P(1) = 300

We need to find P(8).

$dP = kt^{1/2} dt$

$\int 1 dP = \int kt^{1/2} dt$

$P(t) = k \left(\frac{t^{3/2}}{3/2}\right)+c$

$P(t)= \frac{2k}{3}t^{3/2} + c$

When P(0) = 300

$300 = \frac{2k}{3} (0)^{3/2} + c$

∴ c = 300

∴ $P(t)= \frac{2k}{3}t^{3/2} + 300$

When P(1) = 800

$800 = \frac{2k}{3} (1)^{3/2} + 300$

$500 = \frac{2k}{3}$

∴ k = 750

$P(t)= 500t^{3/2} + 300$

So, P(8) is

$P(t)= 500(8)^{3/2} + 300$

= 11,614

So the population becomes 11,614 after 8 days.

8 0

3 years ago

X/24 = 30/36 pls help i might know the answer but i want someone to confirm it

gavmur [86]

Answer:

Step-by-step explanation:

x/24 = 30/36 simplify

x/24 = 5/6 divide 24 by 6 is 4; multiply 4 by 5

x= 20

3 0

3 years ago