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Reptile [31]
3 years ago
7

Which right prism would have the same volume as a square prism with a base area of 36 m2 and a height of 3 m?

Mathematics
1 answer:
OLEGan [10]3 years ago
7 0

Answer:second option

Step-by-step explanation:

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Doss [256]
I'm pretty sure it would be 118 but I might be wrong
8 0
2 years ago
Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm
VladimirAG [237]

Answer:

y=2x^2-4x-8

Step-by-step explanation:

<u>Factored form of a parabola</u>

y=a(x-p)(x-q)

where:

  • p and q are the x-intercepts.
  • a is some constant.

Given x-intercepts:

  • (1+√5, 0)
  • (1-√5, 0)

Therefore:

\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))

\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})

To find a, substitute the given point (4, 8) into the equation and solve for a:

\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8

\implies a(3-\sqrt{5})(3+\sqrt{5})=8

\implies4a=8

\implies a=2

Therefore, the equation of the parabola in factored form is:

\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})

Expand so that the equation is in standard form:

\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)

\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)

\implies y=2(x^2-2x-4)

\implies y=2x^2-4x-8

6 0
1 year ago
7/8 + ___ = 1 what is the missing numbers
Bezzdna [24]

the missing number is 1/8 i hope this helps chu

4 0
3 years ago
HELP! How do I complete this table?
zloy xaker [14]

Answer:

6 1/2

Step-by-step explanation:

i don't know the rest but I know that that one might be 6 1/2

4 0
2 years ago
The surface area for a rectangular prism with a square base is SA=2s2+4sh.
umka21 [38]
2*2*2=8+4*2*4=40 ....
6 0
3 years ago
Read 2 more answers
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