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sveticcg [70]
2 years ago
8

The picture below shows a right-triangle-shaped charging stand for a gaming system:

Mathematics
2 answers:
Andreas93 [3]2 years ago
6 0
Answer is 3(tan)50 degrees
BaLLatris [955]2 years ago
4 0

Answer:

3(tan 50°)

Step-by-step explanation:

I don't really get the question tho...

Hopefully it helps, tho!

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What is the greatest common factor of 18,42,24?
Dmitry_Shevchenko [17]
6 is the gcf of all those numbers
3 0
3 years ago
Pls help will give brainliest
kari74 [83]
4.3x(3.9 - 8.5) + 2.3y(-6.2 - 9.1)......when x = -2.1 and y = 3.5
4.3x(-4.6) + 2.3y(-15.3) 
4.3(-2.1)(-4.6) + 2.3(3.5)(-15.3)
-9.03(-4.6) + 8.05(-15.3)
41.538 - 123.165 
-81.627 <===
4 0
3 years ago
Suppose a standard twelve-hour clock now shows a time of 10:45 what time will the clock show in a 100 hour from now
o-na [289]
It should show 2:45. You can use 12 hr increments to get you back to 10:45 and 12 goes into 100 nine times bringing it to 96. Because of that you have 4 more hours to add to 10:45 and that brings you to 2:45.
4 0
3 years ago
Read 2 more answers
The wildflowers at a national park have been decreasing in numbers. There were 300 wildflowers in the first year that the park s
Scorpion4ik [409]
Although the number of new wildflowers is decreasing, the total number of flowers is increasing every year (assuming flowers aren't dying or otherwise being removed). Every year, 25% of the number of new flowers from the previous year are added.
The sigma notation would be:
∑ (from n=1 to ∞) 4800 * (1/4)ⁿ , where n is the year. 
Remember that this notation should give us the sum of all new flowers from year 1 to infinite, and the values of new flowers for each year should match those given in the table for years 1, 2, and 3
This means the total number of flowers equals:
Year 1: 4800 * 1/4 = 1200 ]
+
Year 2: 4800 * (1/4)² = 300
+ 
Year 3: 4800 * (1/4)³ = 75
+  
Year 4: 4800 * (1/4)⁴ = 18.75 = ~19 (we can't have a part of a flower)
+
Year 5: 4800 * (1/4)⁵ = 4.68 = ~ 5
+ 
Year 6: 4800 * (1/4)⁶ = 1.17 = ~1
And so on. As you can see, it in the years that follow the number of flowers added approaches zero. Thus, we can approximate the infinite sum of new flowers using just Years 1-6:
1200 + 300 + 75 + 19 + 5 + 1 = 1,600

8 0
3 years ago
An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
2 years ago
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