All categories

2 years ago

Tell whether the ratios form a proportion. 1/3, 7/21

Mathematics

2 answers:

Mandarinka [93]2 years ago

7 0

Answer:

i would say yes

my work :

so i did 21 times 1 which is 21.

Tben i did 3 times 7 which is also 21.

So in conclusion i would say yes but i can't guarantee that

Anuta_ua [19.1K]2 years ago

6 0

Answer:

Yes

Step-by-step explanation:

7/21 -> Divide both sides by 7 which gets you 1/3

You might be interested in

For the cereal box, name each of the following

zaharov [31]

Answer:

AB , AD , EF , EH all intersect AE ⇒ answer (c)

Step-by-step explanation:

∵ AE segment passing through A and E

∴ Each segment passing through A and E intersects AE

∴ AB intersects AE at A

∴ AD intersects AE at A

∴ EF intersects AE at E

∴ EH intersects AE at E

∴ The answer is (c)

Step-by-step explanation:

8 0

3 years ago

What is the equation of a line, in point-slope form, that passes through (-8, 1)and has a slope of ?

Serggg [28]

Answer:

y-1 = 5(x+8)

Step-by-step explanation:

The standard equation of a line in point slope form is expressed as;

y-y0 = m(x-x0)

m is the slope

(x0, y0) is the point

Given

Slope m = 5 (assumed value)

Point (-8,1)

Substitute the given data's into the formula

y -1 = 5(x-(-8))

y-1 = 5(x+8)

Hence the required equation is y-1 = 5(x+8)

8 0

2 years ago

Please me with my math

Katyanochek1 [597]

Answer:

8/9, $\sqrt{2}$ , 11/5, $\sqrt{9\\}$ , π, 11/3, 5

Step-by-step explanation:

Simplify and this should be the answer

7 0

3 years ago

Read 2 more answers

How many fewer throws travelled more than 6 3/4 meters than travelled 6 3/4 meters or less

bekas [8.4K]

Answer:

this is not a complete question cause u did not give full numbers

Step-by-step explanation:

not trying to steal points can u finish the question

4 0

3 years ago

The Identity function i behaves just like the number 1. That is (F o i)=f and (i o g)= g

andrezito [222]

I'll denote the identity function by $\mathrm{Id}$ . Then for any functions $f$ with inverse $f^{-1}$ ,

$\begin{cases}f\circ\mathrm{Id}=f\\\mathrm{Id}\circ f=f\\f\circ f^{-1}=\mathrm{Id}\end{cases}$

One important fact is that composition is associative, meaning for functions $f,g,h$ , we have

$(f\circ g)\circ h=f\circ(g\circ h)$

So given

$h=f\circ g$

we can compose the functions on either side with $g^{-1}$ :

$h\circ g^{-1}=(f\circ g)\circ g^{-1}=f\circ(g\circ g^{-1})$

then apply the rules listed above:

$h\circ g^{-1}=f\circ\mathrm{Id}=f$

3 0

3 years ago