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3 years ago

PLS HELP ME WITH 8. A and B (SHOW WORK!!) + LOTS OF POINTS!

Mathematics

1 answer:

Lady bird [3.3K]3 years ago

6 0

To find cost per each you divide $18 by 8 and get $2.25 per book.
To find how much for $27 you divide by $2.25 and get 12 books

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3 to the x power - 1 = 9 to the x power+2

Tom [10]

So we need to solve:

3ˣ⁻¹ = 9ˣ⁺²

To do this, we need to have the same base for both sides of the equation.

So let's go with the base of 3.

3² = 9

3ˣ⁻¹ = (3²)ˣ⁺²

3ˣ⁻¹ = 3²ˣ⁺⁴

Since the bases are the same now, we need to get rid of them and we would get:

x - 1 = 2x + 4

Subtract both sides by 2x:

-x - 1 = 4

Add 1 to both sides:

-x = 5

Divide both sides by -1:

x = -5

8 0

3 years ago

Convert this decimal into its fractional<br> form, simplified completely.<br> 0.700

Diano4ka-milaya [45]

Answer:

7/10...............

8 0

4 years ago

Read 2 more answers

Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable

bekas [8.4K]

Answer:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

$u=\frac{y}{x}$

Multiply both sides by x:

$ux=y$

Second step: Differentiate the substitution:

$u'x+u=y'$

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

$u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}$

$u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}$

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of $x^2$ so I'm going to divide top and bottom by $x^2$ :

$u'x+u=\frac{u+u^2}{3+u^2}$

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

$u'x=\frac{u+u^2}{3+u^2}-u$

Find a common denominator: Multiply second term on right hand side by $\frac{3+u^2}{3+u^2}$ :

$u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}$

Combine fractions while also distributing u to terms in ( ):

$u'x=\frac{u+u^2-3u-u^3}{3+u^2}$

$u'x=\frac{-u^3+u^2-2u}{3+u^2}$

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

$u' \frac{3+u^2}{-u^3+u^2-2u}x=1$

Divide both sides by x:

$\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}$

Reorder the top a little of left hand side using the commutative property for addition:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0

3 years ago

HELP A GIRL OUT please

ivanzaharov [21]

Answer:

I GOT YOU GIRLLL!!

= D. 10.4cm

Step-by-step explanation:

a^2+ b^2=c2

3^2+10^2=c2

9+100=c2

109=c2

$\sqrt{109}$ = $\sqrt{c^{2} }$

10.4=c

8 0

3 years ago

micheal jordan has 72 basketballs,84 baseballs and 48 gold balls and he wants to group them together so that he can donate them

Marianna [84]

They all can be divided by 12 which is the largest number they can be divided by so 12

5 0

3 years ago