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Butoxors [25]
3 years ago
14

Find the product. -7(8 + k)

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0
The product = -56 -7k
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A researcher plants 22 seedlings. After one month, independent of the other seedlings, each seedling has a probability of 0.08 o
Andrews [41]

Answer:

E(X₁)= 1.76

E(X₂)= 4.18

E(X₃)= 9.24

E(X₄)= 6.82

a. P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= 0.00022

b. P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= 0.000001

c. P(X₁≤2) = 0.7442

Step-by-step explanation:

Hello!

So that you can easily resolve this problem first determine your experiment and it's variables. In this case, you have 22 seedlings (n) planted and observe what happens with the after one month, each seedling independent of the others and has each leads to success for exactly one of four categories with a fixed success probability per category. This is a multinomial experiment so I'll separate them in 4 different variables with the corresponding probability of success for each one of them:

X₁: "The seedling is dead" p₁: 0.08

X₂: "The seedling exhibits slow growth" p₂: 0.19

X₃: "The seedling exhibits medium growth" p₃: 0.42

X₄: "The seedling exhibits strong growth" p₄:0.31

To calculate the expected number for each category (k) you need to use the formula:

E(XE(X_{k}) = n_{k} * p_{k}

So

E(X₁)= n*p₁ = 22*0.08 = 1.76

E(X₂)= n*p₂ = 22*0.19 = 4.18

E(X₃)= n*p₃ = 22*0.42 = 9.24

E(X₄)= n*p₄ = 22*0.31 = 6.82

Next, to calculate each probability you just use the corresponding probability of success of each category:

Formula: P(X₁, X₂,..., Xk) = \frac{n!}{X_{1}!X_{2}!...X_{k}!} * p_{1}^{X_{1}} * p_{2}^{X_{2}} *.....*p_{k}^{X_{k}}

a.

P(X₁=3, X₂=4, X₃=6;0.08,0.19,0.42)= \frac{22!}{3!4!6!} * 0.08^{3} * 0.19^{4} * 0.42^{6}\\ = 0.00022

b.

P(X₁=5, X₂=5, X₄=7;0.08,0.19,0.31)= \frac{22!}{5!5!7!} * 0.08^{5} * 0.19^{5} * 0.31^{7}\\ = 0.000001

c.

P(X₁≤2) = \frac{22!}{0!} * 0.08^{0} * (0.92)^{22} + \frac{22!}{1!} * 0.08^{1} * (0.92)^{21} + \frac{22!}{2!} * 0.08^{2} * (0.92)^{20} = 0.7442

I hope you have a SUPER day!

8 0
3 years ago
Solve for q 2/3=-1/3q
tensa zangetsu [6.8K]
Q in (-oo:+oo)

2/3 = (1/3)*q // - (1/3)*q
                                                                  
2/3-((1/3)*q) = 0                                             
                                                                       ddddddddd
                                                                       d              d      
                                                                       d              d
(-1/3)*q+2/3 = 0                                              d              d
                                                                       d              d
2/3-1/3*q = 0 // - 2/3                                       d              d
                                                                       d              d
-1/3*q = -2/3 // : -1/3                                       d              d
                                                                       d              d
q = -2/3/(-1/3)                                    ddddddd               dddddddd     
                                                     dd                                               dd
q = 2                                            dd                                                 dd
                                                    dd                   dddd                      dd
q = 2                                              dddddddddd          dddddddddddd
6 0
3 years ago
Jade and Eros practice piano over the weekend.
skad [1K]
50 minutes - 20 minutes = 30 minutes. Eros practiced for 30 more minutes than Jade.
4 0
3 years ago
How do you write 0.3 as a fraction?
dimaraw [331]

Answer:

3/10

Hope it helps

7 0
3 years ago
Read 2 more answers
(a)/(2a)+(4)/(3a^(2)) ayuda por favor
Irina-Kira [14]

Answer:

3a^2+8/6a^2

Step-by-step explanation:

there ya go hope this helps

5 0
2 years ago
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