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Ierofanga [76]
2 years ago
7

Average of -4.05 3.1 and eight

Mathematics
1 answer:
vodka [1.7K]2 years ago
5 0

Answer:

2.35

Step-by-step explanation:

-4.05 + 3.1 + 8 = 7.05/3=2.35

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Anita has a cellphone contract that costs her R100 per month plus 85 cents per peak time SMS,and 25 cents per off-peak time SMS.
algol [13]

Answer:

Anita's monthly bill will be $164.25.

Step-by-step explanation:

Since Anita has a cellphone contract that costs her R100 per month plus 85 cents per peak time SMS, and 25 cents per off-peak time SMS, if she sends 45 SMSs during peak time and 105 SMSs during off-peak time In a month To determine what will her monthly bill come to, the following calculation must be performed:

100 + (0.85 x 45) + (0.25 x 105) = X

100 + 38.25 + 26.25 = X

138.25 + 26.25 = X

164.25 = X

Therefore, her monthly bill will be $ 164.25.

6 0
3 years ago
Someone plz help me litterly no one would bother to help me so plz I beg of u due today
goldfiish [28.3K]

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

Answer:

I'm going to help youuuuu.

Step-by-step explanation:

{1}

Your answer is A) because the rise/run is -2/4x, which simplifies to -1/2x, which is <em>option A)</em>.

{2}

Dario's salary is <em>B) $12 per hour</em>. This is because, in 5 hours, Dario makes 60 dollars. If you find the unit rate of $60 in 5 hours, the answer is $12 per hour.

{3}

A) Between <em>x = -6</em> and <em>x = -2</em>

I hope this helps! I am sorry if any of these are incorrect!

- sincerelynini

8 0
3 years ago
Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li
krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years

First, let us calculate the decay constant (k)

75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036

Next, let us calculate the half-life as follows:

\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2}  \approx 669\ years

Therefore the half-life is between 600 and 700 years

5 0
2 years ago
Which set of angles can form a triangle
kow [346]
Answer is c explanation
7 0
3 years ago
Read 2 more answers
A car's gas tank that is 40% full contains 12 gallons of gas. Show the math you used to find the maximum capacity of the gas tan
Lisa [10]

Answer: 30 gallons

Step-by-step explanation:

So fist we add 40% and $40%. That's 80 percent of the tank which is 12 + 12 = 24. Then we figure out half of 40 percent which is 20 which means its 6 gallons. Now we add. 12+12+6 which equals our answer 30 gallons

3 0
3 years ago
Read 2 more answers
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