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3 years ago

Given f(x) = 7x-2, what is the value of f(2)?

Mathematics

2 answers:

Nimfa-mama [501]3 years ago

8 0

Answer: 12

Step-by-step explanation: f(x) = 7x - 2 means that if we put an <em>x</em> into our function, a 7x -2 comes out.

So if we want to find f(2), that means we are putting a 2 into our function which means that a 7(2) - 2 comes out which simplifies

to 14 - 2 or 12. So f(2) = 12.

motikmotik3 years ago

7 0

Answer:

f(2)=12

Step-by-step explanation:

f(x)=7x-2

Plug 2 into the equation, since it says "f(2)".

f(x)=7(2)-2

f(x)=14-2

f(x)=12, done!

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What is the answer to |x-4|<13

VARVARA [1.3K]

Answer:

<h2>The solution is -9 < x < 17.</h2>

Step-by-step explanation:

|x-4|<13.

The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.

Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.

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3 years ago

The average summer vacation costs $2252. If 82% of this amount is charged on credit cards, then what amount of the vacation cost

expeople1 [14]

Answer: $1846.64

Step-by-step explanation:

Given : The average summer vacation costs $2252.

If 82% of this amount is charged on credit cards, then the amount of the vacation cost is charged will be :-

$82\%\text{ of }\$2252\\\\\text{Convert percent into fraction by dividing it by 100, we get}\\\\=\$[\dfrac{82}{100}\times2252]\\\\=\$[\dfrac{184664}{100}]\\\\=\$1846.64$

Therefore the amount of the vacation cost is charged= $1846.64

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2 years ago

1. if csc β = 7/3 and cot β = - 2√10 / 3, Find sec β

slava [35]

Step-by-step explanation:

$\tan \beta = \frac{1}{ \cot \beta } = - \frac{3}{2 \sqrt{10} } = - \frac{3 \sqrt{10} }{20}$

$\csc \beta \tan \beta = \frac{1}{ \cos \beta } = \sec \beta$

Therefore,

$\sec \beta = ( \frac{7}{3} )( - \frac{3 \sqrt{10} }{20} ) = - \frac{7 \sqrt{10} }{20}$

$\csc y = \frac{1}{ \sin y} = - \frac{ \sqrt{6} }{2}$

$= > \sin y = - \frac{ \sqrt{6} }{3}$

Use the identity

$\cos y = \sqrt{1 - \sin ^{2} y} \: \: \: \: \: \: \: \: \: \: \: \\ = \sqrt{1 - {( - \frac{ \sqrt{6} }{3}) }^{2} } = - \frac{ \sqrt{3} }{3}$

We chose the negative value of the cosine because of the condition where cot y > 0. Otherwise, choosing the positive root will yield a negative cotangent value. Now that we know the sine and cosine of y, we can now solve for the tangent:

$\tan \beta = \frac{ \sin y}{ \cos y} =( - \frac{ \sqrt{6} }{3} )( - \frac{3}{ \sqrt{3} } ) = \sqrt{2}$