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meriva
4 years ago
14

You can use automatic link-checking software to identify invalid hyperlinks. If you find invalid links, what should you do next?

a. Manually update the code to delete or modify invalid links.
b. Run the link-checking software in Fix Invalid Links mode.
c. Use the link-checking software to re-create all links in your code.
d. Re-create the page from scratch to ensure that all code is fresh and valid.
Computers and Technology
1 answer:
KengaRu [80]4 years ago
7 0

Answer:

B. Run the link-checking software in Fix Invalid Links mode.

Explanation:

Web design and development is the use of web development tools to build a web site. A web site can have a single page or multiple pages. Html is a markup language used to create web pages. The html link tag "<a>" is used to create hyperlinks on a page which can direct the user to related pages on the site or to other websites.

Broken hyperlinks on a web page can be identified and fixed at the same time using third party software or online applications.

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Write a program which:
Studentka2010 [4]

Answer:

Ill do this in C# and Java

Explanation:

C#:

public static void Main(string[] args)

       {

           string input = Console.ReadLine();

               switch (input)

               {

                   case "A1":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Shoes");

                       break;

                   case "B1":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("Jackets");

                       break;

                   case "C1":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Trousers");

                       break;

                   case "A2":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Trainers");

                       break;

                   case "B2":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("TShirts");

                       break;

                   case "C2":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Shorts");

                       break;

                   default:

                       Console.WriteLine("Incorrect Input");

                       break;

               }

       }

Java:

public static void main(String[] args)

   {

       Scanner myObj = new Scanner(System.in);  // Create a Scanner object

       String input = myObj.nextLine();

       {

           switch (input)

               {

                   case "A1":

                       System.out.println("Footwear:");

                       System.out.println("Shoes");

                       break;

                   case "B1":

                       System.out.println("Tops:");

                       System.out.println("Jackets");

                       break;

                   case "C1":

                       System.out.println("Pants:");

                       System.out.println("Trousers");

                       break;

                   case "A2":

                       System.out.println("Footwear:");

                       System.out.println("Trainers");

                       break;

                   case "B2":

                       System.out.println("Tops:");

                       System.out.println("TShirts");

                       break;

                   case "C2":

                       System.out.println("Pants:");

                       System.out.println("Shorts");

                       break;

                   default:

                       System.out.println("Incorrect Input");

                       break;

               }

       }

3 0
4 years ago
Write an algorithm and draw a flowchart to count the digits present in the given integer. ​
saul85 [17]

Answer:

The algorithm is as follows:

Input number  

count = 0

while(number not equal 0)

   number = number / 10

   count = count + 1

end

Print count

Explanation:

This gets input for the integer number

 Input number  

This initializes count of digits to 0

count = 0

The following loop is repeated while number is not 0

while(number not equal 0)

This performs integer division of the number by 10; the resulting division is saved in variable number

   number = number / 10

The count variable is incremented by 1

   count = count + 1

The loop ends here

end

This prints the count of integers

Print count

<em>See attachment for flowchart</em>

8 0
3 years ago
PLZ HELP 20 POINTS I REALLY NEED TO GET THIS RIGHT!
DIA [1.3K]

Answer:

B. 12

Explanation:

A4=A1+2

A1=10

10+2=12

A4=12

Ihope this helps

4 0
4 years ago
Quickly Please!!!
Alex
:)holding the control and pressing home
7 0
3 years ago
Read 2 more answers
In a class named InputTextToOutputFile.java use the following prompt to get the fileName of the output file from the user: "What
grin007 [14]

Answer:

Detailed program code is written at explaination

Explanation:

Program:

import java.io.File;

import java.io.FileWriter;

import java.io.IOException;

import java.util.Scanner;

public class InputTextToOutputFile

{

public static void main(String[] args) throws IOException

{

Scanner in=new Scanner(System.in);//Scanner object to get user input

System.out.println("What is the name of your output file? ");

String fileName = in.nextLine();//get output file name

File file = new File(fileName);//File object with fileName as input

//Create the file by method file.createNewFile()

if (file.createNewFile())

{

System.out.println("File is created!");

} else {

System.out.println("File already exists.");

}

//FileWriter object with user file name given as input

FileWriter writer = new FileWriter(file);

System.out.println("Enter text to write to a file : ");

String line;//variable to store line content

do {

line=in.nextLine();//get line content from user

writer.write(line+"\n"); //write content to file by adding new line(\n) character

}while(!line.equals("STOP!"));//repeat a loop until user enters "STOP!" line

writer.close();//close the file object

}

5 0
4 years ago
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