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Novay_Z [31]
3 years ago
15

The exploitation of a buffer-overrun vulnerability in an application will MOST likely lead to:_________

Computers and Technology
1 answer:
SashulF [63]3 years ago
8 0

Answer:

A. Arbitrary code execution

Explanation:

A buffer-overrun, also known as buffer overflow occurs when a programmer makes an error during coding, which could make his system easily susceptible to attacks from a hacker. The root cause of this problem is an overflow of data in a buffer, and programs that are written in C and C+ + are more likely to be affected by this problem.  When a buffer-overrun occurs, it would most likely lead to arbitrary code execution.

Arbitrary code execution is an uncontrolled and unrestricted coding by the attacker which alters the original coding. The attacker could input more information into the coding, which alters the original information and which would make the application porous and accessible by just anyone. It is important that programmers run regular tests on their programs, so as to detect any coding errors.

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Which principle suggests that specific single responsibility interfaces are better than one general purpose interface?
ElenaW [278]

Answer:Interface segregation principle

Explanation: Interface-segregation principle (ISP) is amongst the major principles of the object-oriented design which describes that none of the users/clients can be forced for indulging and depending on the unknown methods or methods that they don't have knowledge about.

It functions by making the interfaces visible to the user that specifically fascinates them and keeping other smaller interfaces.Interfaces are made by splitting process and making the small interfaces from them.

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3 years ago
What is the price of a k1 speed birthday party?
valentinak56 [21]
There is differen prices depending on the race go to the k1 website to see the packages
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3 years ago
Read 2 more answers
When breaking a problem down, you often encounter elements that you want to use repeatedly in your code. Sometimes it's appropri
ddd [48]

<u>Answer:</u>

<em>FUNCTION:</em>

  • A function does not require the number of times that the <em>code script needs to be executed </em>
  • When we go for large programming, ie. while creating projects, we can invoke function from one file to another based on the access <em>specifier mentioned for the function. </em>
  • There is a stack call created in the memory whenever a <em>function is called. </em>

<em>LOOP :</em>

  • Whereas the number of times that the loop has to be <em>executed must be defined </em>
  • A loop cannot be called, it can be used only the code block in <em>which it is present. </em>
  • There is not overhead of creating a stack since it is not invoked and there is no <em>transfer of control from one module to another </em>

8 0
3 years ago
Traditionally, remote administrative access on routers was configured using Telnet on TCP port 23. However, Telnet was developed
FinnZ [79.3K]

<u>Explanation</u>:

It is an all-too-often used technology today in connecting several computers together via a network.

Routing simple terms means the action of selecting the path taken by the traffic of data in a network of computers. The routing systems involve the use of both wireless and cable based architectures. Some common example of routing systems includes:

  1. Dynamic Routing
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5 0
3 years ago
Write the definition of a method dashedLine, with one parameter, an int. If the parameter is negative or zero, the method does n
ZanzabumX [31]

Answer:

import java.util.Scanner;

public class DashLine {

public static void main(String[] args) {

// Declaring variables

int n;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print("Enter a number :");

n = sc.nextInt();

// calling the method by passing the user entered input as argument

dashedLine(n);

}

//This method will print the dashed line for number greater than zer

private static void dashedLine(int n) {

if (n > 0) {

for (int i = 1; i <= n; i++) {

System.out.print("-");

}

System.out.println();

}

}

}

Explanation:

5 0
3 years ago
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