Answer:
y = 2
Step-by-step explanation:
Given
![\sqrt[3]{3y+2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3y%2B2%7D)
+ 4 = 6 ( subtract 4 from both sides )
= 2 ( cube both sides )
3y + 2 = 2³ = 8 ( subtract 2 from both sides )
3y = 6 ( divide both sides by 3 )
y = 2
Answer:
I'm not good with the type of math on 3, so I'm going to answer 4. (P.S I don't know the question you're asking, so I'm going to assume you want to know the area and perimeter of the shapes.
Step-by-step explanation:
To solve number 4 I added the width of the 2 triangles to give me the width of the rectangle, so then 2 times 9 is 18. Then for the triangles. The formula for triangles is base times height divided by 2. So we add the areas of all shapes and we get: 18+6+24=48m. So the area for number 4 is 48 meters.
(hope this was your question)
Answer:
7/20
Step-by-step explanation:
given,
2r = 7/10
r= 7/10*1/2
r= 7/20
Use PEMDAS
first 36-4 = 32
7^2 = 49
(32/16) - 49 is your answer -47
Answer:
Try CEGI
Step-by-step explanation:
if it's wrong im sorry-
