Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
Answer is D you can plug it in to check it as well
Answer:
The answer is B
Step-by-step explanation:
Yes I think so I apologize if not
Answer:
1600/49
Step-by-step explanation:
5 5/7 = 40/7
40/7 * 40/7 = 1600/49
