like horror movies hate horror movies total
like animated 21 22 43
doesn't like animated 56 3 59
total 77 25 102
if a student likes horror movies (there are 77 of them)...what is the probability that student also like animated movies.....21/77 or 27%
Given:
(3x^4 - 2 + 8x^3 ) + (7x^3 - 6 + 7x^4 )
Add like terms together ( same variables and exponents )
3x^4 + 7x^4 +8x^3 + 7x^3 -2 - 6
10x^4 + 15x^3 - 8
Answer :
10x^4 + 15x^3 - 8
Answer:
B
Step-by-step explanation:
Consider an event A happening. If we do not have enough data to estimate its actual probability, we may choose a range 0.6 to 0.9 as a first case which indicates we are quite sure it will most likely occur. If however, we have enough data, we may estimate a range of 0.7 to 0.8 as a second case that is more certain on its actual likelihood of occurrence.
Say the actual probability of the event is given as 0.75, in the first case, we can infer the probability interval as 0.75 ± 0.15 (as 0.75-0.15=0.6 and 0.75+0.15=0.9 for the lower and upper bounds respectively). In the second case, we can infer the probability interval as 0.75±0.05 (as 0.75-0.05=0.7 and 0.75+0.05=0.8 for the lower and upper bounds respectively).
Thus, we can see that with more certainty of the event happening (with more data in this case), the probability or prediction intervals are lower.
Hence, in the experiment, we will observe a narrower prediction interval for researcher A who has more (twice as many points) data than researcher B who has fewer points.
Answer:
Step-by-step explanation:
7 fruit tart chews. If he eats one piece every 10 minutes, what is the probability his first two pieces will be a jelly treat and a mint stick? ... First you add all the candies together to get 20 in the bag 2+11+7=20 jelly treat: ... Paul has a bag with 6 mint sticks, 9 jelly treats, and 5 fruit tart chews. If he eats one ...
