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g100num [7]
3 years ago
14

What values of a and b make the equation true? sqrt(648)=sqrt(2^a•3^b)

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0
ANSWER

The value of a and b are:

a=3,b=4

EXPLANATION

The expression given to us is

\sqrt{648} = \sqrt{ {2}^{a} \times {3}^{b} }

We square both sides of the equation to obtain

648= {2}^{a} \times {3}^{b}

We now find the prime factorization of 648 to obtain,

{2}^{3} \times {3}^{4} = {2}^{a} \times {3}^{b}

We now compare the exponents on both sides of the equation to obtain,

a=3,b=4

Therefore the correct option is C
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