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Eduardwww [97]
3 years ago
9

Find the missing height

Mathematics
1 answer:
mash [69]3 years ago
4 0

Answer:

hbjfgvvshdjkhdgfadhshdgbacfdbashnahsfdgshdgfdhsdgshasdshasgdsgdfdgs

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I solved some of it but now I don't know if you continue it correctly ... To be performed: (lesson: Raducali of order "n")
nikitadnepr [17]

Answer:

-9

Step-by-step explanation:

( \sqrt[4]{7}  + 2)( \sqrt[4]{7}  - 2)( \sqrt{7}  + 4) \\  = ( { \sqrt[4]{7} }^{2}  - {{2} }^{2} )( \sqrt{7}  + 4) [because (a+b)(a-b) = a² - b²]\\  = ( \sqrt{7}  - 4)( \sqrt{7}  + 4) \\  =   { \sqrt{7} }^{2}  -  {4}^{2}[because (a+b)(a-b) = a² - b²]  \\  = 7 - 16 \\  =  - 9

5 0
3 years ago
Read 2 more answers
What does the time say ?
cricket20 [7]

Answer: it’s 6:00 pm

Step-by-step explanation:

4 0
3 years ago
Determine whether the given vectors are orthogonal, parallel, or neither. (a) a = 9, 6 , b = −4, 6 orthogonal parallel neither (
labwork [276]

Answer:

(a) Orthogonal, (b) Neither, (c) Parallel, d( Orthogonal

Step-by-step explanation:

a and b are parallel is a=kb

a and b if a dot b = 0

(a) a dot b = (9)(-4)+6(6)=-36+36=0

  a and b are orthogonal

(b) a dot b = 40-7-21=12

    a=kb -> there is no k value satisfying the equation

    a and b are neither parallel or orthogonal

(c) a dot b = -12-108-48=-168

    a=kb  -> k=-3/4 satisfies the equation

    a and b are parallel

(d) a dot b= 9-3-6=0

  a and b are orthogonal

5 0
3 years ago
Please help answer number 4!
solong [7]
The image is black, what’s the question?
4 0
3 years ago
8x83x8303x838x83x9993x93939x99393
Zolol [24]

Answer:

3.5778559e+25

Step-by-step explanation:

8 0
3 years ago
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