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kati45 [8]
3 years ago
5

Identify the false statement: The synthesizer generates sounds electronically. Synthesis refers to creating sounds electronicall

y from electronically generated waveforms. Synthesizers have always had a well-established presence in standard ensembles. On the synthesizer, timbre and volume depend on the waveform.
Physics
2 answers:
levacccp [35]3 years ago
7 0

Answer:

"Synthesizers have always had a well-established presence in standard ensembles."

Explanation:

This is an opinion. Not a true statement.

frozen [14]3 years ago
7 0

Answer:

Explanation:

I think the questionable statement is that Synthesizers have always been a well established presence in standard ensembles. The very earliest ones that were in common use came out in the 60s and 70s. A great many pieces of music had no use for them before that time. The Classical period lacked the electronics (completely) to make use of such modern equipment.

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Calculate the displacement in m and velocity in m/s at the following times for a rock thrown straight down with an initial veloc
svet-max [94.6K]

Incomplete question as time is missing.I have assumed some times here.The complete question is here

Calculate the displacement and velocity at times of (a) 0.500 s, (b) 1.00 s, (c) 1.50 s, (d) 2.00 s, and (e) 2.50 s for a rock thrown straight down with an initial velocity of 10 m/s from the Verrazano Narrows Bridge in New York City. The roadway of this bridge is 70.0 m above the water.

Explanation:

Given data

Vi=10 m/s

S=70 m

(a) t₁=0.5 s

(b) t₂=1 s

(c) t₃=1.5 s

(d) t₄=2 s

(e) t₅=2.5 s

To find

Displacement S from t₁ to t₅

Velocity V from t₁ to t₅

Solution

According to kinematic equation of motion and given information conclude that v is given by

v=v_{i}+gt\\

Also get the equation of displacement

S=v_{i}t+(1/2)gt^{2}

These two formula are used to find velocity as well as displacement for time t₁ to t₅

For t₁=0.5 s

v_{1}=v_{i}+gt\\v_{1}=(10m/s)+(9.8m/s^{2} ) (0.5s)\\v_{1}=14.9m/s\\  And\\S_{1} =v_{i}t+(1/2)gt^{2}\\ S_{1}=(10m/s)(0.5s)+(1/2)(9.8m/s^{2} )(0.5s)^{2} \\S_{1}=6.225m

For t₂

v_{2}=v_{i}+gt\\v_{2}=(10m/s)+(9.8m/s^{2} ) (1s)\\v_{2}=19.8m/s\\  And\\S_{2} =v_{i}t+(1/2)gt^{2}\\ S_{2}=(10m/s)(1s)+(1/2)(9.8m/s^{2} )(1s)^{2} \\S_{2}=14.9m

For t₃

v_{3}=v_{i}+gt\\v_{3}=(10m/s)+(9.8m/s^{2} ) (1.5s)\\v_{3}=24.7m/s\\  And\\S_{3} =v_{i}t+(1/2)gt^{2}\\ S_{3}=(10m/s)(1.5s)+(1/2)(9.8m/s^{2} )(1.5s)^{2} \\S_{3}=26.025m

For t₄

v_{4}=v_{i}+gt\\v_{4}=(10m/s)+(9.8m/s^{2} ) (2s)\\v_{4}=29.6m/s\\  And\\S_{4} =v_{i}t+(1/2)gt^{2}\\ S_{4}=(10m/s)(2s)+(1/2)(9.8m/s^{2} )(2s)^{2} \\S_{4}=39.6m

For t₅

v_{5}=v_{i}+gt\\v_{5}=(10m/s)+(9.8m/s^{2} ) (2.5s)\\v_{5}=34.5m/s\\  And\\S_{5} =v_{i}t+(1/2)gt^{2}\\ S_{5}=(10m/s)(2.5s)+(1/2)(9.8m/s^{2} )(2.5s)^{2} \\S_{5}=55.625m

4 0
4 years ago
A box measures 4 m x 3 m x 2 m would it be easier to push the box if it were resting on a 3 m x 2 m side or on the 4 m x 3 m sid
ozzi

Answer:

465408754m468 iui m456m

4 0
3 years ago
A 200kg bumper car moving 3 m/s collides head on with a 392kg bumper car moving 6m/s. After impact, the larger car continues tra
Maru [420]

Answer:

the final speed of the smaller car is 5.624 m/s

Explanation:

Given;

mass of the small car, m₁ = 200 kg

initial velocity of the small car, u₁ = 3 m/s

mass of the larger car, m₂ = 392 kg

initial velocity of the larger car, u₂ = 6 m/s

final velocity of the larger car, v₂ = 1.6 m/s

let the direction of the larger car be positive

let the direction of the smaller car be negative

Apply the principle of conservation of linear momentum to determine the final speed of the smaller car.

m₁u₁ + m₂u₂ = m₁v₁  +  m₂v₂

200(-3)  +  392(6)  = 200v₁   +  392 x 1.6

-600 + 2352  = 200v₁    +  627.2

1752   =  200v₁     +   627.2

1752  -  627.2     =  200v₁

1124.8  = 200v₁

v₁  =  1124.8/200

v₁ = 5.624 m/s

Therefore, the final speed of the smaller car is 5.624 m/s

7 0
3 years ago
During a sunny afternoon, the sun suddenly seems much less bright than usual. The daylight seems much less intense, as if there
Tatiana [17]

Answer:

D). A sudden change in temperature increased the density of the atmosphere.

Explanation:

The claim that can be made and supported with evidence regarding the temporary decrease in light would be 'a sudden change in temperature will increase the density of the atmosphere.' <u>As the temperature increases, the molecules in the atmosphere begin to move fastly which causes a decrease in atmosphere density while it increases with the fall in temperature. As a result, the intensity of sunlight gets affected due to molecules being heavier and floating in the atmosphere</u>. Thus, <u>option D</u> is the correct answer.

8 0
3 years ago
1. You and a friend are spending the weekend making up missed lab experiments. You are on to second semester material and are st
goldenfox [79]

Answer:

D) ¼ as large

Explanation:

The magnitude of the electric force between two charges is

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1 and q2 are the magnitudes of the two charges

r is the separation between them

From the formula we see that the magnitude of the force is inversely proportional to the square of the distance.

In this problem, the distance is doubled:

r'=2r

So the new force will be

F'=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}k\frac{q_1 q_2}{r^2}=\frac{1}{4}F

So the force will decrease to 1/4 of its original value.

8 0
4 years ago
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