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AnnZ [28]
3 years ago
7

Use the accompanying seismogram to answer which of the three types of seismic waves reached the seismograph first.

Physics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

Primary waves (P-waves)

Explanation:

Due to excess of the energy inside the earth when the tectonic plates begin to slide or fracture then the energy is released in the form of seismic waves, this causes the earthquake.

<u>Two types of seismic waves are generally responsible for the earth quakes:</u>

  1. body waves
  2. surface waves

Body waves are of two types:

Primary waves (P-waves)

These are the fastest of all the waves involved in the earth-quake which travel at a speed of 1.6 km to 8 km per second.

They can pass trough solids, liquids and gases. They arrive at the surface as an instant thud.

Secondary waves (S-waves)

They can only pass through the solids and they move slower than the P-waves.

As S-waves move, they displace the rock particles, pushing them outwards perpendicular to the wave-path that leads to the earthquake-related first rolling period.

Surface waves (L-waves/ long waves)

  • These waves move along the surface of the earth. They are responsible for the earthquake's carnage.
  • They move up and down the Earth's surface, rocking the foundations of man-made structures.
  • Surface waves are slowest of the three waves, which means that they are the last to arrive. So at the end of an earthquake usually comes the most powerful shaking.
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A ball is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
vovangra [49]

Answer:

a) 48.5 ft/s

b) 36.5 ft

c) -80.3 ft/s

Explanation:

a)

The equation of motion of the ball is :

y(t) = -16.1 ft/s^2 * t^2 + Vo*t

Where Vo is the initial velocity

If y(5s) = - 160 ft:

-160 ft = -16.1 ft/s^2 * (5 s)^2 + Vo*(5s)

Solving for Vo

Vo  = (16.1*25- 160) ft / 5s = 48.5 ft/s

b)

To answer this question we must first know when the velocity became zero, at this time is when the ball was at its highest point.

v(t) = -32.2 ft/s^2 * t + Vo

t = Vo/32.2ft/s^2 = 1.5 s

And now, the highest point which the ball reached is given by:

y(1.5s) = -16.1 ft/s^2 * (1.5)^2 + Vo*(1.5s)

y(1.5s) = 36.52 ft

c)

We now need the time at which y(t') = -64 ft

-64 = -16.1*t'^2 + 48.5*t'

By means of the quadratic formula, we find that

t' = 4.00498 s ≈ 4 s

And the velocity at t = 4s is:

v(4s) = -32.2 ft/s^2 * 4s +48.5 ft/s = -80.3 ft/s

3 0
3 years ago
A box of weight 74 N is sliding on a horizontal surface at a constant velocity due to an external force F-&gt; of magnitude 4.8
n200080 [17]

Answer

4.8 N

If the box is moving with a constant velocity, then we can say that the system is in equilibrium. This is because if the external force (F->) was greater than other forces the box would be accelerating. This tells us that this force (F->) is just enough to overcome friction and so it must be equal to 4.8 N.

The normal force has no effect to the horizontal velocities or forces. It is equal to -Weight. That is -74 N. The negative sign shows that the force is in opposite direction.

6 0
3 years ago
Mohs scale is used in describing which characteristic? luster toughness hardness crystal form
Lady_Fox [76]
The answer is hardness not luster 

3 0
3 years ago
Read 2 more answers
In the table below,which statement would best fill the missing box under isolated systems?
Nostrana [21]

Answer:

b-energy is not exchanged

Explanation:

An isolated system is a thermodynamic system in which neither energy nor matter is exchanged with the surroundings.

As such the best statement that will fill the box under an isolated system is that energy is not exchanged.

  • In an open system, both matter and energy are exchanged with the surrounding.
  • A closed system is one in which energy transfer is permissible but matter is not exchanged.
  • Energy cannot be created nor destroyed in any system. They are simply transformed.
3 0
3 years ago
A student sits in a chair that can spin without friction. The student has her hands outstretched and starts rotating at 1.9 rev/
Airida [17]

Answer:

the resulting angular speed after she pulls her hand inwards in (rad/s)  is  27.02 rad/s

Explanation:

Given that :

the initial angular speed \omega_1 = 1.9 \ \ rev/s

Initial rotational inertia I_1 = 12.00 \ \ kg.m^2

Final angular speed \omega_2 = ???

Final rotational inertia I_2 = 5.3 \ \ kg.m^2

According to conservation of momentum :

Initial momentum = final momentum

I_1 \omega_1 = I_2 \omega_2

\omega_2 = \frac{I_1 \omega_1}{I_2}

\omega_2 = \frac{12.00*1.9}{5.3}

\omega_2 = 4,3 rev/s

To rad/s ; we have:

1  \   rev/s = 2 \pi \ \  rad/s

\omega_2 = 4.3 * 2 \pi \ \  rad/s

\omega_2 = 27.02  \ \ rad/s

Therefore the resulting angular speed after she pulls her hand inwards in (rad/s) = 27.02 rad/s

8 0
3 years ago
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