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KiRa [710]
2 years ago
5

A crate of oranges is shoved across a grocery store floor with a force of 100 N for a distance of 1 meter. The crate travels an

additional 1 meter after the shove and stops just short of the display. You can conclude: the magnitude of work done by frictional forces on the crate is 100 J the magnitude of work done by the applied force on the crate is 100 J the magnitude of the force of friction on the crate is 50 N all of the above conclusions are correct none of the above conclusions are correct
Physics
1 answer:
navik [9.2K]2 years ago
4 0

The statements that are true are;

  • the magnitude of work done by frictional forces on the crate is 100 J
  • the magnitude of work done by the applied force on the crate is 100 J
<h3>What is work done?</h3>

Work is said to be done when te force applied travels a distance in the direction of the force. Now we can see that when the force is applied by shoving the crate, work is done, an additional work is done by friction to bring the crate to a stop.

Hence, the following are true;

  • the magnitude of work done by frictional forces on the crate is 100 J
  • the magnitude of work done by the applied force on the crate is 100 J

Learn more about work: brainly.com/question/18094932?

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A child and sled with a combined mass of 58.0 kg slide down a frictionless slope. If the sled starts from rest and has a speed o
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Answer:

The height is  h = 0.5224 \ m

Explanation:

From the question we are told that

   The combined mass of the child and the sled is  m =  58.0 \  kg

    The  speed of the sled is  u = 3.20 \ m/s

Generally applying SOHCAHTOA on the slope which the combined mass is down from

   Here the length of the slope(L)  where the combined mass slides through  is the hypotenuses

   while the height(h) of the height of the slope is the opposite

Hence from SOHCAHTOA

      sin (\theta) =  \frac{h}{L}

=>   Lsin(\theta) = h

Generally from the kinematic equation we have that

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Here the u  is the initial velocity of the combined mass which is zero since it started from rest

 and  a is the acceleration of the combined mass which is mathematically evaluated as

       a =  g * sin (\theta )

      v^2  = u^2 + 2 *  g * sin (\theta )L

=>   2Lsin(\theta ) =  \frac{v^2 - u^2 }{g}

=>   h = \frac{ v^2 - u^2}{2g}

=>   h = \frac{ 3.20^2 - 0^2}{2 * 9.8 }

=>   h = 0.5224 \ m

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