The quadratic term is 2x^2.
For this case we have the following inequality:
![\frac{x-9}{7x+2} \leq 0](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx-9%7D%7B7x%2B2%7D%20%20%5Cleq%200)
Solving for the numerator we have:
![x \leq 9](https://tex.z-dn.net/?f=x%20%20%5Cleq%209)
Solving for the denominator we have:
![x \ \textgreater \ \frac{-2}{7}](https://tex.z-dn.net/?f=x%20%5C%20%5Ctextgreater%20%5C%20%20%20%5Cfrac%7B-2%7D%7B7%7D%20)
Therefore, the solution is given by:
![\frac{-2}{7} \ \textless \ x \leq 9](https://tex.z-dn.net/?f=%20%5Cfrac%7B-2%7D%7B7%7D%20%5C%20%5Ctextless%20%5C%20%20x%20%20%5Cleq%209%20)
The graph that shows this solution is the graphic number 3.
Answer:
option 3
Answer:
D.
Step-by-step explanation:
Given that,
Shelley's pet food store sold one customer 5 peanut butter biscuits for $3. She sold another customer 7 beef treats for $4.20.
For peanut, the cost is ratio is
![\dfrac{5}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B3%7D)
For beef, the ratio is
![\dfrac{7}{4.2}](https://tex.z-dn.net/?f=%5Cdfrac%7B7%7D%7B4.2%7D)
If we take cross product of these items,
![\dfrac{5}{3}=\dfrac{7}{4.2}\\\\5\times 4.2=3\times 7\\\\21=21](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B3%7D%3D%5Cdfrac%7B7%7D%7B4.2%7D%5C%5C%5C%5C5%5Ctimes%204.2%3D3%5Ctimes%207%5C%5C%5C%5C21%3D21)
It implies, that the sale is in true proportion. From the cross product, we find that it is equal.