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Luba_88 [7]
2 years ago
15

What is the slope of the line through the points (-2, -1) and (8, -3)

Mathematics
2 answers:
KiRa [710]2 years ago
5 0

Answer:

The slope of the line through the points (-2,-1) and (8,-3) is -0.2.  Have a nice day and hope this helps.



Alex777 [14]2 years ago
5 0

Answer:

The answer is -0.2

Step-by-step explanation:

In order to determine the slope of the line, we have to know about how calculate a slope.

There are two ways of get a slope of a line:

  1. Knowing the linear equation and then we need to free the "y" variable (dependent variable). The coefficient of the "x" variable (independent variable) is the slope.
  2. From to two points that belong to the linear equation.

The formula of the second way is the next:

m=slope of the linear equation

P1=(x1,y1)=first pair of coordinate

P2=(x2,y2)=second pair of coordinate

m=\frac{y_2-y_1}{x_2-x_1}

In this case, we have two points, so we use the formula:

P1=(-2,-1)

P2=(8,-3)

m=\frac{-3-(-1)}{8-(-2)}\\ \\m=\frac{-3+1}{8+2} \\\\m=\frac{-2}{10} \\\\m=-0.2

Finally, the slope of the line is -0.2

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A function f(x)=3x+12.
seraphim [82]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2822258

_______________


•  Function:   f(x) = 3x + 12.


A.  Finding the inverse of f.

The composition of f with its inverse results in the identity function:

(f o g)(x) = x

f[ g(x) ] = x

3 · g(x) + 12 = x

3 · g(x) = x – 12

              x – 12
g(x)  =  ⸺⸺
                 3

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               3

________


B.  Verifying that the composition of f and g gives us the identity function:

•  \mathsf{(f\circ g)(x)}

\mathsf{=f\big[g(x)\big]}\\\\\\ \mathsf{=3\cdot \left(\dfrac{x}{3}-4\right)+12}\\\\\\&#10;\mathsf{=\diagup\hspace{-7}3\cdot \dfrac{x}{\diagup\hspace{-7}3}-3\cdot 4+12}\\\\\\&#10;\mathsf{=x-12+12}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}


and also

•  \mathsf{(g\circ f)(x)}

\mathsf{=g\big[f(x)\big]}\\\\\\ \mathsf{=\dfrac{f(x)}{3}-4}\\\\\\ \mathsf{=\dfrac{3x+12}{3}-4}\\\\\\&#10;\mathsf{=\dfrac{\diagup\hspace{-7}3\cdot (x+4)}{\diagup\hspace{-7}3}-4}\\\\\\&#10;\mathsf{=x+4-4}\\\\&#10;\mathsf{=x\qquad\quad\checkmark}

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C.  Since f and g are inverse, then

f(g(– 2))

= (f o g)(– 2)

= – 2          <span>✔
</span>

•  Call h the compositon of f and g. So,

h(x) = (f o g)(x)

h(x) = x


As you can see above, there is no restriction for h. Therefore, the domain of h is R (all real numbers).


I hope this helps. =)

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A ghhuhggfgghhhhhjkhhj
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