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alekssr [168]
4 years ago
11

Can a relative minimum also be an absolute minimum

Mathematics
1 answer:
Tatiana [17]4 years ago
8 0
No not exactly because a related minimum has an end point.

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Hailey is scuba diving in the ocean. Her boat is anchored 300 feet away at a 30° angle of depression. If her diving partner is 2
victus00 [196]

Answer:

B)313 ft

Step-by-step explanation:

Hello,I think I can help you with this

to solve this you need to find all the measures of the rigth triangle formed by Hailey, the boat, and the point on the surface of the sea just above the head of Hailey

Step 1

define

triangle

Hypotenuse=300 feet

opposite side=y

adjacent side=x

angle of depression =30°

Step 2

find the distances

cos\alpha =\frac{adjancent\ side}{hypotenuse}\\\\hypotenuse*cos\alpha =adjancent\ side\\ so\\x=adjancent\ side=hypotenuse*cos\alpha\\\\x=300\ft*cos 30 \\\\x=259.8076

so,  the point on the surface of the sea just above hailey is 259.8076 ft from the boat

sin\alpha =\frac{opposite\ side}{hypotenuse}\\\\hypotenuse*sin\alpha \\y=opposite\ side\\ so\\y=opposite\ side=hypotenuse*sin\alpha\\\\y=300\ft*sin 30 \\\\y=150

hailey is at a depth of 150 feet

Step 3

now,her partner is 25 feet directly below her,it is

partner's depth is =hailey is at a depth of 150 feet+25

Y=175

he is at the same distance from de boat ( horizontal),because it is the same point in the sea surface.

X=259.80

Step 4

to find  the distance between the partner and the boat we can use  

Pythagoras theorem

adjacentside^{2} +opposite side^{2} =hypotenuse^{2} \\\sqrt[2]{adjacentside^{2} +opposite side^{2}} =Hypotenuse\\Hypotenuse=\sqrt[2]{175^{2} +259.8076^{2}} \\\\Hypotenuse=313.24 ft

so, Hailey's diving partner is 313 ft away from the boat(B)

Have a great day.

3 0
3 years ago
Explain how you can use model to find 6x17
Karo-lina-s [1.5K]
You can use lattice multiplication or long multiplication. for examples and/or visuals message me.
8 0
4 years ago
Read 2 more answers
Use the table below to determine whether or not the cost to hire a web designer is a linear function of the number of hours work
almond37 [142]
Answer: B) Non Linear

In order to find out whether a table is linear or not, the numbers have to have a constant rate of change. in order to see whether they do have a constant rate of change or not, try to count the difference between each number on one side, then the other, and see if the difference is the same.

For instance, the total cost numbers go from $205 to $400, which is a $195 difference. Then it goes from $400 to $595, which is again a $195 difference, but pay attention to how it goes from $595 to $725, which is a $130 difference. That $130 difference automatically makes the graph non linear, since the rate of change for the total cost isn’t a constant $195. Just to be sure, you can check the other side as well.

The Hours go from 2 to 5 (3 hour difference), then 5 to 8 (another 3 hour difference), but then 8 to 10. Since the rate of change isn’t 3 hours through the entire Hour side, the table doesn’t have a constant rate of change, which makes this table a non linear function.

If a table doesn’t have a constant rate of change, it’s non-linear. If a table does have a constant rate of change, it is linear. In this case, since the table doesn’t have a constant rate of change, it’s not linear. This responses is kinda long, but I hope it helped!
3 0
2 years ago
The value 5pi/24 is a solution for the equation 4 cos^2 (4x)-3=0. True or false
Margaret [11]

Let's check.

x = 5π/24

4x = 5π/6

cos 4x = cos(5π/6) = cos 150° = -√3/2

cos² 4x = (-√3/2)^2 = 3/4

4 cos² 4x  -3  = 4 (3/4) - 3 = 0

Answer: TRUE

5 0
4 years ago
A construction worker needs to put lights on a pole 420 centimeters off the ground. How many meters off the ground do the lights
evablogger [386]

Answer:

4.2 meters

Step-by-step explanation:

The height that the lights will be put is 420 centimeters, and the question asks how many meters off the ground the lights need to be placed, so to solve the question we just need to convert 420 centimeters to meters.

We know that 1 meter is equal to 100 centimeters, so we can solve this using a rule of three:

100 centimeters -> 1 meter

420 centimeters -> X meters

100/420 = 1/X

X = 420/100 = 4.2 meters

The lights need to be placed on the pole at 4.2 meters off the ground.

5 0
3 years ago
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