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inysia [295]
3 years ago
5

Which inequality represents all values of x for which the product below is defined?

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0

Step 1 ) Separate the 4 and x.

\displaystyle\sqrt{4x} * \sqrt{x+2}

↓

\displaystyle\sqrt{4} \sqrt{x} \sqrt{x+2}

Step 2 ) Simplify the square root of 4.

\displaystyle\sqrt{4} \sqrt{x} \sqrt{x+2}

↓

\displaystyle\ 2 \sqrt{x} \sqrt{x+2}

Step 3 ) Simplify.

\displaystyle\ 2 \sqrt{x} \sqrt{x+2}

↓

\displaystyle\ 2 \sqrt{x(x+2)}

This is now in its simplest form, so the final answer is...

\displaystyle\ 2 \sqrt{x(x+2)}

or it could be...

\displaystyle\ 2 \sqrt{x} \sqrt{x+2}

Either one is correct. Only difference is one is in simplest form and one isn't.

•

•

- Marlon Nunez

julsineya [31]3 years ago
6 0

Answer: x>_0

Step-by-step explanation:

a p e x

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Step-by-step explanation:


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3 years ago
the length of a new rectangle playing field is 6 yards longer than quadruple the width. if the perimeter of the rectangle plaing
Vika [28.1K]

The length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

<h3>What is the area of the rectangle?</h3>

It is defined as the area occupied by the rectangle in two-dimensional planner geometry.

The area of a rectangle can be calculated using the following formula:

Rectangle area = length x width

We have:

The length of a new rectangle playing field is 6 yards longer than quadruple the width.

Let's suppose the length is l and width is w of a rectangle:

From the problem:

l = 6 + 4w

Perimeter P = 2(l + w)

532 = 2(l + w)

Plug l = 6+4w in the above equation:

532 = 2(6 + 4w + w)

266 = 6 + 5w

260 = 5w

w = 52 yards

l = 6 +4(52) = 214 yards

Thus, the length and width of a new rectangle playing field are 214 yards and 52 yards respectively.

Learn more about the area of rectangle here:

brainly.com/question/15019502

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2 years ago
Factorize (4d-3e)2 +6d(4d-3e)​
Natasha_Volkova [10]

Answer:

(4d - 3e)(10d - 3e)

Step-by-step explanation:

(4d - 3e)² + 6d(4d - 3e) ← factor out (4d - 3e) from each term

= (4d - 3e)(4d - 3e + 6d) ← collect like terms inside parenthesis

= (4d - 3e)(10d - 3e)

4 0
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