A triangle has three sides of length x, x+4, and 2x-1. The perimeter of the triangle is 27.

Mathematics

1 answer:

Andru [333]2 years ago

6 0

Answer:

6.10,11

Step-by-step explanation:

x+x+4+2x-1=27

4x+3=27

4x=27-3

4x=24

x=24/4=6

x+4=6+4=10

2x-1=2×6-1=11

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Find parametric equations and symmetric equations for the line. (Use the parameter t.) The line through (4, −5, 2) and parallel

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Answer:

Step-by-step explanation:

From the given information, the symmetric equations for the line pass through(4, -5, 2) i.e ( $x_o, y_o, z_o$ ) and are parallel to $\dfrac{x+5}{1} = \dfrac{y}{2}= \dfrac{z-3}{1}$

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$x = x_o + at \\ \\ x = y_o + bt \\ \\ x = z_o + ct$

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y = -5 + 2t

z = 2 + t

Thus, x, y, z = ( 4+t, -5+2t, 2+t )

The symmetric equation can now be as follows:

$\begin {vmatrix} x = 4+ t \\ \\ \dfrac{x-4}{1} = t \begin {vmatirx} \end {vmatrix}$ $\begin {vmatrix} y = - 5+2t \\ \\ \dfrac{y+5}{2} =t \end {vmatrix}$ $\begin {vmatrix} z =2+t \\ \\ \dfrac{z-2}{1} =t \end {vmatrix}$