Answer:
Time,t that it will elapse before the concerntration of the dye in the tank reaches1% of its original value is 460.52 seconds
Step-by-step explanation:
Let Q(t) = amount of dye for all time,t.
Let Q'= rate in - rate out.
But Q/200 = concerntration of dye
Therefore rate out= Q/200 ×2.
Q'/Q = - 1/100
Dividing by Q gives
Ln/Q/ + c = -1/100t + c1
Integrating both sides with respect to t
Ln/Q/ = -1/100t + c2.
c1 and c1 are just another constants
Q= c3e^-t/100
Exponentiating both sides will cause the absolute values to get absorbed into the constants giving rise to a new constant c3
200= c3-0/100
c3= 200
2= 200e^-t/100
Ln1/100= - t/100
Ln0.01 = - t/ 100
Cross multiply
t= Ln0.01 × 100
t = 4.6052 ×100
t = 460.52seconds
Answer:
(-2,0) (1,0) (6,0)
Step-by-step explanation:
I used synthetic division which is a lot to explain so I would recommend googling it
Answer:
(2y+50)+(7x-248)=180 (solve for x and y) supplementary angles add up to 180 and these two angles are supplementary complements
(5y-17) + (x+44) = 180 (solve for x and y)
Step-by-step explanation:
I hope this helps you
if 2 cm 21 km
9cm ? km
?×2=9×21
?=189÷2
?=94,5 km
