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elena-14-01-66 [18.8K]
3 years ago
6

Maria and Katy each have a piece of string. When they put the two pieces of string together end to end, the total length is 84in

ches. Maria’s string is 6 inches longer than Katy’s. How long is Maria’s piece of string? How long is Katy’s piece of string
Mathematics
1 answer:
kramer3 years ago
3 0

Maria's piece is 45 inches long

Katy's piece is 39 inches long

Step-by-step explanation:

Maria and Katy each have a piece of string

  • When they put the two pieces of string together end to end, the total length is 84 inches
  • Maria’s string is 6 inches longer than Katy’s

We need to find how long is Maria’s piece of string and how long is Katy’s piece of string

Assume that the length of Maria's piece is x inches and the length of Katy's piece is y inches

∵ Maria's piece is x inches

∵ Katy's piece is y inches

∵ The total length of the two pieces is 84 inches

- Add x and y, then equate the sum by 84

∴ x + y = 84 ⇒ (1)

∵ Maria’s string is 6 inches longer than Katy’s

- That means equate x by the sum of y and 6

∴ x = y + 6 ⇒ (2)

Now we have a system of equations to solve it

Substitute x in equation (1) by equation (2)

∴ (y + 6) + y = 84

- Add the like terms in the left hand side

∴ 2y + 6 = 84

- Subtract 6 from both sides

∴ 2y = 78

- Divide both sides by 2

∴ y = 39

- Substitute the value of y in equation (2) to find x

∵ x = 39 + 6

∴ x = 45

Maria's piece is 45 inches long

Katy's piece is 39 inches long

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
If 13cos theta -5=0 find sin theta +cos theta / sin theta -cos theta​
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Step-by-step explanation:

<h3>Need to FinD :</h3>

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\red{\frak{Given}} \begin{cases} & \sf {13\ cos \theta\ -\ 5\ =\ 0\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \big\lgroup Can\ also\ be\ written\ as \big\rgroup} \\ & \sf {cos \theta\ =\ {\footnotesize{\dfrac{5}{13}}}} \end{cases}

Here, we're asked to find out the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0. In order to find the solution we're gonna use trigonometric ratios to find the value of sinθ and cosθ. Let us consider, a right angled triangle, say PQR.

Where,

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  • QR = Adjacent side
  • RP = Hypotenuse
  • ∠Q = 90°
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As we know that, 13 cosθ - 5 = 0 which is stated in the question. So, it can also be written as cosθ = 5/13. As per the cosine ratio, we know that,

\rightarrow {\underline{\boxed{\red{\sf{cos \theta\ =\ \dfrac{Adjacent\ side}{Hypotenuse}}}}}}

Since, we know that,

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So, we will find the PQ (Opposite side) in order to estimate the value of sinθ. So, by using the Pythagoras Theorem, we will find the PQ.

Therefore,

\red \bigstar {\underline{\underline{\pmb{\sf{According\ to\ Question:-}}}}}

\rule{200}{3}

\sf \dashrightarrow {(PQ)^2\ +\ (QR)^2\ =\ (RP)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ (5)^2\ =\ (13)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ 25\ =\ 169} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 169\ -\ 25} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 144} \\ \\ \\ \sf \dashrightarrow {PQ\ =\ \sqrt{144}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{PQ\ (Opposite\ side)\ =\ 12}}}}_{\sf \blue{\tiny{Required\ value}}}}

∴ Hence, the value of PQ (Opposite side) is 12. Now, in order to determine it's value, we will use the sine ratio.

\rightarrow {\underline{\boxed{\red{\sf{sin \theta\ =\ \dfrac{Opposite\ side}{Hypotenuse}}}}}}

Where,

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Therefore,

\sf \rightarrow {sin \theta\ =\ \dfrac{12}{13}}

Now, we have the values of sinθ and cosθ, that are 12/13 and 5/13 respectively. Now, finally we will find out the value of the following.

\rightarrow {\underline{\boxed{\red{\sf{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}}}}}}

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\rule{200}{3}

\sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\Big( \dfrac{12}{13}\ +\ \dfrac{5}{13} \Big)}{\Big( \dfrac{12}{13}\ -\ \dfrac{5}{13} \Big)}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\dfrac{17}{13}}{\dfrac{7}{13}}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{13} \times \dfrac{13}{7}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{\cancel{13}} \times \dfrac{\cancel{13}}{7}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{7}}}}}_{\sf \blue{\tiny{Required\ value}}}}

∴ Hence, the required answer is 17/7.

6 0
3 years ago
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pogonyaev
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have a nice day and i hope this helps :)
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