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2 years ago

If f(x)=x^2 + 8x find f(d-3)

1 answer:

7 0

F(x)=x^2 +8x
f(d-3) basically what we get from this is that the x value is d-3
to find f(d-3) simply plug in d-3 for every x
f(d-3)=(d-3)^2 + 8(d-3)
that would be one form of the answer, but we can also continue multiplying it out
f(d-3)= d^2-6d+9+8d-24
add like terms
f(d-3)=d^2+2d-15

have a nice day and i hope this helps :)

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If (cos)x= 1/2 what is sin(x) and tan(x)? Explain your steps in complete sentences.

Natasha_Volkova [10]

The correct answers are:
1) sin(x) = $\frac{ \sqrt{3} }{2}$
2) tan(x) = $\sqrt{3}$

Explanation:
Given:
$cos(x) = \frac{1}{2}$

Step 1:
Since, according to the Trigonometric identity:
$sin^2(x) + cos^2(x) = 1$ -- (1)

Step 2:
Plug in the value of cos(x) in equation (1):
$sin^2(x) + ( \frac{1}{2} )^2 = 1 \\ sin^2(x) + \frac{1}{4} = 1 \\ sin^2(x) = \frac{3}{4}$

Step 3:
Take square-root on both sides:
$\sqrt{sin^2(x)} = \sqrt{\frac{3}{4}}$

sin(x) = $\frac{ \sqrt{3} }{2}$

Now to find the tan(x), we would use the following formula:

tan(x) = $\frac{sin(x)}{cos(x)}$ --- (2)

Plug in the values of sin(x) and cos(x) in equation (2):
tan(x) = $\frac{ \frac{ \sqrt{3} }{2} }{ \frac{1}{2} }$

Hence tan(x) = $\sqrt{3}$

6 0

3 years ago

Read 2 more answers

Show how Carly can work out 171/2% of 240 in her head

KATRIN_1 [288]

17 ½ % of 240

First option

Change the fraction ½ to a decimal. It would be 0.5 ( 1 divided by 2)

½=0.5

You will add the whole number 17 to the result.

17 + 05 = 17.5

Now you will divide by 100 (percent)

17.5 /100 To divide a decimal by 100, move the decimal point two places to the left.

17.5 /100 = 0.175 times 240

0.175 x 240 = 42

Second option

Change the percent to an improper fraction

17 ½= 35/2 (you have to multiply (2 x 17) plus 1 equals 35 over 2 ( keep the denominator). It will be 35/2. Put the other number (240) over 100 and multiply.

35/2 x 240/100 = 42

There is another way . You can simplify

Cancel all the zeros that you have and start to reduce.

7 12

35 x 24<span> 0 </span> = 42

2 10 0

1 5

17 ½ % of 240 = 42

5 0

3 years ago

Solve |x + 7| < 6<br> its for homework

Semmy [17]

Ok so if you follow the process of pemdas is should be easy pemdas equals: parentheses, exponents, multiple and divide from left to right, lastly add and subtract from left to right

3 0

2 years ago

The equation of line v is y = -x + 9. Line w, which is perpendicular to line v, includes the

Oduvanchick [21]

Answer:

y=x+1

Step-by-step explanation:

In order to find the slope that is perpendicular to a given line, you have to take the fraction form (-1/1), flip it (1/-1), and give it an opposite sign (1/1). Now since we now know our slope we can draw y=x to find what do we have to add. Since y=x crosses (2,2), we know we have to add 1 to the equation in order to bring it to (2, 3).

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3 years ago

Two circles with different radii have chords AB and CD, such that AB is congruent to CD. Are the arcs intersected by these chord

emmainna [20.7K]

The arcs intersected by these chords are not congruent.

Given that two circles with different radii have chords AB and CD, such that AB is congruent to CD.

Let r₁ and r₂ be the radii of two different circles with centers O and O' respectively.

Assuming that the each of the ∠АОВ and ∠CO'D is less than or equal to π.

Then, we have isosceles triangle AOB and CO'D such that,

AO = OB = r₁,

CO' = O'D = r₂,

Let us assume that r₁< r₂;

We can see that arc(AB) intersected by AB is greater than arc(CD), intersected by the chord CD;

arc(AB) > arc(CD) .......(1)

Indeed,

arc(AB) = r₁ angle (AOB)

arc(CD) = r₂ angle (CO'D)

So, we have to prove that ;

∠AOB >∠CO'D ......(2)

Since each angle is less than or equal to π, and so

∠AOB/2 and ∠CO'D/2 is less than or equal to π

it suffices to show that :

tan(AOB/2) >tan(CO'D/2) ......(3)

From triangle AOB :

tan(AOB/2) = AB/(2*r₁)

tan(CO'D/2) = CD/(2*r₂)

Since AB = CD and r₁ < r₂ (As obtained from the result of (3) ), therefore, arc(AB) > arc(CD).

Hence, for two circles with different radii have chords AB and CD, such that AB is congruent to CD but the arcs intersected by these chords are not congruent.

Learn more about congruent from here brainly.com/question/1675117

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6 0

1 year ago