Question

If x+y= -4 and xy=2, then find the value of x²+y²​

Answer 1

X+y = -4
Xy=2

(x+y)^2= x^2+y^2+2xy
(-4)^2=x^2+y^2+2(2)
16 = x^2+y^2+4
x^2+y^2=16-4
Therefore x^2+y^2 = 12

Answer 2

Answer:

x² + y² = 12

Step-by-step explanation:

x + y = -4

xy = 2

x² + y² = (x+y)² - 2xy = (-4)² - 2(2) = 16 - 4 = 12