Answer:
The probability that at least 280 of these students are smokers is 0.9664.
Step-by-step explanation:
Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers
The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.
But the sample selected is too large and the probability of success is close to 0.50.
So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
1. np ≥ 10
2. n(1 - p) ≥ 10
Check the conditions as follows:

Thus, a Normal approximation to binomial can be applied.
So,

Compute the probability that at least 280 of these students are smokers as follows:
Apply continuity correction:
P (X ≥ 280) = P (X > 280 + 0.50)
= P (X > 280.50)

*Use a <em>z</em>-table for the probability.
Thus, the probability that at least 280 of these students are smokers is 0.9664.
Answer:
I think the first quartile is 30
Step-by-step explanation:
To find the quartiles you would look at the end points of the box.
Answer:
the number of adult ticket sold is 107 tickets
Step-by-step explanation:
The computation of the number of adult ticket sold is shown below:
Let us assume the number of tickets be x,
So, the adult be x
And for student it would be 3x
Students= 2x
Adults= x
Total = 4x
Now the equation could be
4x = 428
x = 107
This x signifies the adult tickets sold i.e 107
Hence, the number of adult ticket sold is 107 tickets
Median of (72 82 92 93 94 97 98 102)
Median: 93.5
MAD : 7.125
Median of ( 53 59 64 65 65 66 67 69)
Median : 65
MAD : 3.75