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icang [17]
3 years ago
7

How to find the mean of 2, 7, 6, 1, 9, 2, 4, 9

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

Answer:

5

Step-by-step explanation:

Add the numbers together, then divide that by the amount of numbers

(2 + 7 + 6 + 1 + 9 + 2 + 4 + 9)/8

40/8 = 5

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Alonzo invested his savings in two investment funds. The amount he invested in Fund A was $2000 less than the amount he invested
alina1380 [7]

Answer:

There were $13,200 in Fund B.

Step-by-step explanation:

We are given the following in the question:

Let x be the amount in Fund A and y be the amount in Fund B.

The amount he invested in Fund A was 2000$ less than the amount he invested in Fund B.

Thus, we can write the equation:

x = y -2000

Profit percent on Fund A = 7%

Profit percent on Fund B = 8%

Total profit = $1960

Thus, we can write the equation:

7\%(x) + 8\%(y) = 1960\\7x + 8y = 196000

Solving the two equations by substitution, we get,

7(y-2000) + 8y = 196000\\\Rightarrow 15y = 198000\\\Rightarrow y = 13200\\\Rightarrow x = 11200

Thus, there were $13,200 in Fund B.

4 0
3 years ago
Solve by quadratic equation​
Ymorist [56]
<h2>Question :</h2>

  • \tt \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}

<h2>Answer :</h2>

  • \large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}

<h2>Explanation :</h2>

\tt : \implies \dfrac{x+2}{x-2} + \dfrac{x-2}{x+2} = \dfrac{5}{6}

\tt : \implies \dfrac{(x+2)(x+2) + (x-2)(x-2)}{(x-2)(x+2)} = \dfrac{5}{6}

\tt : \implies \dfrac{(x+2)^{2} + (x-2)^{2}}{(x-2)(x+2)} = \dfrac{5}{6}

<u>Now, we know that</u> :

  • \large \underline{\boxed{\bf{(a+b)^{2} = a^{2} + b^{2}+ 2ab}}}
  • \large \underline{\boxed{\bf{(a-b)^{2} = a^{2} + b^{2} - 2ab}}}
  • \large \underline{\boxed{\bf{(a+b)(a-b) = a^{2} - b^{2}}}}

\tt : \implies \dfrac{x^{2}+2^{2}+ 2 \times x \times 2 + x^{2}+2^{2} - 2 \times x \times 2 }{x^{2}-2^{2}} = \dfrac{5}{6}

\tt : \implies \dfrac{x^{2}+ 4 + \cancel{4x} + x^{2}+ 4 - \cancel{4x}}{x^{2}-4} = \dfrac{5}{6}

\tt : \implies \dfrac{x^{2} + x^{2} + 4 + 4}{x^{2}-4} = \dfrac{5}{6}

\tt : \implies \dfrac{2x^{2} + 8}{x^{2}-4} = \dfrac{5}{6}

<u>By cross multiply</u> :

\tt : \implies (2x^{2} + 8)6= 5(x^{2}-4)

\tt : \implies 12x^{2} + 48 = 5x^{2}-20

\tt : \implies 12x^{2} + 48 - 5x^{2} + 20 = 0

\tt : \implies 7x^{2} + 68 = 0

\tt : \implies 7x^{2} + 0x + 68 = 0

<u>Now, by comparing with ax² + bx + c = 0, we have</u> :

  • a = 7
  • b = 0
  • c = 68

<u>By using quadratic formula</u> :

\large \underline{\boxed{\bf{x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}}}}

\tt : \implies x = \dfrac{-(0) \pm \sqrt{(0)^{2} - 4(7)(68)}}{2(7)}

\tt : \implies x = \dfrac{0 \pm \sqrt{0 - 1904}}{14}

\tt : \implies x = \dfrac{\pm \sqrt{- 1904}}{14}

\tt : \implies x = \dfrac{\pm \sqrt{2\times 2\times 2\times 2\times 7\times 17}}{14}

\tt : \implies x = \dfrac{\pm \cancel{2} \times 2\sqrt{7\times 17}}{\cancel{14}}

\tt : \implies x = \dfrac{\pm2\sqrt{119}}{7}

\large \underline{\boxed{\bf{x = \dfrac{\pm 2\sqrt{119}}{7}}}}

Hence value of \bf x =\dfrac{\pm 2\sqrt{119}}{7}

5 0
3 years ago
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A patio is a rectangle 12 feet wide and 16 feet long. The patio is completely surrounded by a fence. How long is the fence?
poizon [28]

12+12+16+16 = 56

the fence is 56 feet long

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Sin^2(x/2)=sin^2x <br> Find the value of x
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(2\cos x+1)(\cos x-1)=0
\implies\begin{cases}2\cos x+1=0\\\cos x-1=0\end{cases}\implies\begin{cases}\cos x=-\frac12\\\cos x=1\end{cases}

The first case occurs in 0\le x for x=\dfrac{2\pi}3 and x=\dfrac{4\pi}3. Extending the domain to account for all real x, we have this happening for x=\dfrac{2\pi}3+2n\pi and \dfrac{4\pi}3+2n\pi, where n\in\mathbb Z.

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3 years ago
Poiont S is the midpoint of RT. Complete the statement: ST = 38 ft, RT =
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