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Georgia [21]
3 years ago
10

HELPPPP PLEASE60 POINTS​

Mathematics
2 answers:
Lena [83]3 years ago
8 0

Answer:

1056

Step-by-step explanation:

just add all the area of all square

1² + 4² + 7² + 8² + 9² + 10² +14² +15² + 18² =

1 + 16 + 49 + 64 + 81 + 100 + 196 + 225 + 324 = 1056

or for simple just add two biggest one as the sides of Moron reactangle

15+18 = 33 and 18+14 = 32

the the area should be 32 x 33 = 1056

soldi70 [24.7K]3 years ago
3 0

Answer:

1056

Step-by-step explanation:

Find the area of each square and add them to find the area of the rectangle

The area of a square = side * side

The areas are:

1*1= 1

4*4 = 16

7*7 = 49

8*8 = 64

9*9 = 81

10*10 = 100

14*14 = 196

15*15 = 225

18*18 = 324

The sum of the areas =

324+225+196+100+81+64+49+16+1

= 1056 units ^2

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pls help will give brainliest Rena used the steps below to evaluate the expression (StartFraction (x Superscript negative 3 Base
kaheart [24]

Answer:

  First "order of operations" mistake: step 2

  First arithmetic mistake: step 4

Step-by-step explanation:

As we understand Rena's work, she wants to simplify ...

  \left(\dfrac{x^{-3}y^{-2}}{2x^4y^{-4}}\right)^{-3}

for x = -1 and y = 2.

Her work seems to be ...

<u>Step 1</u>

  \text{Substitute $x=-1$ and $y=2$ into the expression}\\\\\left(\dfrac{(-1)^{-3}2^{-2}}{2(-1)^42^{-4}}\right)^{-3}\qquad\text{no error}

<u>Step 2</u>

  \text{Simplify the parentheses}\\\\\left(\dfrac{2^4}{2(-1)^4(-1)^32^2}\right)^{-3}=\left(\dfrac{2^2}{2(-1)^7}\right)^{-3}\qquad\text{order of operations error}

<u>Step 3</u>

  \text{Evaluate the power to a power}\\\\\dfrac{2^{-6}}{2^{-3}(-1)^{21}}\qquad\text{no error}

<u>Step 4</u>

  \text{Use reciprocals and find the value}\\\\\dfrac{1}{2^32^6(-1)^{21}}=\dfrac{1}{8\cdot 64\cdot (-1)}=\dfrac{-1}{512}\qquad\text{error: $2^3$ is used instead of $2^{-3}$}

_____

So, the first arithmetic error is in Step 4. However, the order of operations requires exponents be evaluated first. Doing that makes step 2 look like ...

  \left(\dfrac{-\dfrac{1}{4}}{2(1)\dfrac{1}{16}}\right)^{-3}=(-2)^{-3}\qquad\text{proper Step 2}

__

We expect your answer is supposed to be Step 4.

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