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damaskus [11]
3 years ago
11

Choose the inverse of y=X2-2

Mathematics
2 answers:
hjlf3 years ago
8 0

For this case we must find the inverse of the following function:

y = x ^ 2-2

We exchange the variables:

x = y ^ 2-2

We clear the variable "y":

Adding 2 to both sides we have:

x + 2 = y ^ 2

Applying square root on both sides of the equation:

y = \pm \sqrt {x + 2}

We change y by f ^ {- 1} (x):f ^ {- 1} (x) =\pm \sqrt {x + 2}

Answer:

f ^ {- 1} (x) = \pm\sqrt {x + 2}

pickupchik [31]3 years ago
7 0

Answer:

26

Step-by-step explanation:

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\frac{3}{2} + \frac{3\sqrt{3} }{2} i

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AVprozaik [17]

Answer:  (x,y) = (-1, 1)

This means that x = -1 and y = 1

========================================================

Explanation:

The first equation says that y is the same as 2x+3

That allows us to substitute y for 2x+3 in the second equation like so:

2x+5y = 3

2x+5( y ) = 3

2x + 5(2x+3) = 3 .... y replaced with 2x+3

2x+10x+15 = 3

12x+15 = 3

12x = 3-15

12x = -12

x = -12/12

x = -1

Then we'll substitute this into the first equation to find y

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y = 2(-1) + 3 .... x replaced with -1

y = -2+3

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Together x = -1 and y = 1 pair up to form the ordered pair solution (x,y) = (-1,1)

If you were to graph y = 2x+3 and 2x+5y=3 on the same xy grid, then you should see that the two lines intersect at the location (-1,1). This is a visual way to determine the solution quickly through use of a graphing calculator.

3 0
3 years ago
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